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3 years ago

Suppose a moving object has a kinetic energy of 100 J. What will the object's kinetic

Physics

1 answer:

Darina [25.2K]3 years ago

4 0

The kinetic energy will quadruple

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

From the equation, we notice that the kinetic energy is:

Directly proportional to the mass
Proportional to the square of the speed

In this problem, the initial kinetic energy of the object is

K = 100 J

Later, the speed of the object is doubled:

v' = 2v

Therefore, the new kinetic energy will be

$K'=\frac{1}{2}m(v')^2=\frac{1}{2}m(2v)^2=4(\frac{1}{2}mv^2)=4K$

So, we see that the kinetic energy will quadruple.

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

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3 years ago

In an RLC series circuit that includes a source of alternating current operating at fixed frequency and voltage, the resistance

maw [93]

Answer:

Capacitive Reactance is 4 times of resistance

Solution:

As per the question:

R = $X_{L} = j\omega L = 2\pi fL$

where

R = resistance

$X_{L} = Inductive Reactance$

f = fixed frequency

Now,

For a parallel plate capacitor, capacitance, C:

$C = \frac{\epsilon_{o}A}{x}$

where

x = separation between the parallel plates

Thus

C ∝ $\frac{1}{x}$

Now, if the distance reduces to one-third:

Capacitance becomes 3 times of the initial capacitace, i.e., x' = 3x, then C' = 3C and hence Current, I becomes 3I.

Also,

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Also,

Z ∝ I

Therefore,

$\frac{Z}{I} = \frac{Z'}{I'}$

$\frac{\sqrt{R^{2} + (R - X_{C})^{2}}}{3I} = \frac{\sqrt{R^{2} + (R - \frac{X_{C}}{3})^{2}}}{I}$

${R^{2} + (R - X_{C})^{2}} = 9({R^{2} + (R - \frac{X_{C}}{3})^{2}})$

${R^{2} + R^{2} + X_{C}^{2} - 2RX_{C} = 9({R^{2} + R^{2} + \frac{X_{C}^{2}}{9} - 2RX_{C})$

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3 years ago

A wire along the z axis carries a current of 6.8 A in the z direction Find the magnitude and direction of the force exerted on a

Alexeev081 [22]

Answer:

Force is 14.93N along positive y axis.

Explanation:

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$\overrightarrow{F}=\overrightarrow{Il}\times \overrightarrow{B}$

where L is the length of the conductor

Applying values in the equation we have force F =

$\overrightarrow{F}=6.8\times 6.1\widehat{k}\times 0.36\widehat{i}\\\\\overrightarrow{F}=41.48\widehat{k}\times 0.36\widehat{i}\\\\\therefore \overrightarrow{F}=14.93N\widehat{j}$

Thus force is 14.93N along positive y axis.

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