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lord [1]
3 years ago
9

Suppose a moving object has a kinetic energy of 100 J. What will the object's kinetic

Physics
1 answer:
Darina [25.2K]3 years ago
4 0

The kinetic energy will quadruple

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

From the equation, we notice that the kinetic energy is:

  • Directly proportional to the mass
  • Proportional to the square of the speed

In this problem, the initial kinetic energy of the object is

K = 100 J

Later, the speed of the object is doubled:

v' = 2v

Therefore, the new kinetic energy will be

K'=\frac{1}{2}m(v')^2=\frac{1}{2}m(2v)^2=4(\frac{1}{2}mv^2)=4K

So, we see that the kinetic energy will quadruple.

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

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Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27
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Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n\times\dfrac{m}{V_{c}\times N_{A}}

n=\dfrac{\rho\timesV_{c}\times N}{m}....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100

\rho=5.98

We calculate the mass of the alloy

m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100

m=111.15

Put the value into the equation (I)

n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

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