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2 years ago

Suppose a moving object has a kinetic energy of 100 J. What will the object's kinetic

Physics

1 answer:

Darina [25.2K]2 years ago

4 0

The kinetic energy will quadruple

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

From the equation, we notice that the kinetic energy is:

Directly proportional to the mass
Proportional to the square of the speed

In this problem, the initial kinetic energy of the object is

K = 100 J

Later, the speed of the object is doubled:

v' = 2v

Therefore, the new kinetic energy will be

$K'=\frac{1}{2}m(v')^2=\frac{1}{2}m(2v)^2=4(\frac{1}{2}mv^2)=4K$

So, we see that the kinetic energy will quadruple.

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

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1 year ago

A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the

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Answer:

It will be cut in half

Explanation:

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2 years ago

A ball of moist clay falls 17.3 m to the ground. It is in contact with the ground for 24.0 ms before stopping. (a) What is the a

gizmo_the_mogwai [7]

Answer:

Acceleration, $767.08\ m/s^2$

Explanation:

Given that,

Height from a ball falls the ground, h = 17.3 m

It is in contact with the ground for 24.0 ms before stopping.

We need to find the average acceleration the ball during the time it is in contact with the ground.

Firstly, find the velocity when it reached the ground. So,

$v^2=u^2+2ah$

u = initial velocity=0 m/s

a = acceleration=g

$v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 17.3} \\\\v=18.41\ m/s$

It is in negative direction, u = -18.41 m/s

Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.

$a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18.41}{24\times 10^{-3}}\\\\a=767.08\ m/s^2$

So, the average acceleration of the ball during the time it is in contact is $767.08\ m/s^2$ .

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2 years ago