All categories

3 years ago

Suppose a moving object has a kinetic energy of 100 J. What will the object's kinetic

Physics

1 answer:

Darina [25.2K]3 years ago

4 0

The kinetic energy will quadruple

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

From the equation, we notice that the kinetic energy is:

Directly proportional to the mass
Proportional to the square of the speed

In this problem, the initial kinetic energy of the object is

K = 100 J

Later, the speed of the object is doubled:

v' = 2v

Therefore, the new kinetic energy will be

$K'=\frac{1}{2}m(v')^2=\frac{1}{2}m(2v)^2=4(\frac{1}{2}mv^2)=4K$

So, we see that the kinetic energy will quadruple.

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

You might be interested in

A boat is traveling upstream in the positive direction of the x axis at 10 km/h with respect to the water of a river. The water

sasho [114]

Answer:

The velocity of the boat with respect to the ground is 3 km/h

Explanation:

The speed of an object is different depending on the reference system you use. This is called relative speed.

A boat travels upstream, this means that it moves in the opposite direction to the river current.

A boat travels upstream, this means that it moves in the opposite direction to the river current. Then, if the boat moves in the positive direction of the x axis at 10 km / h with respect to the water of a river, the water flows in the negative direction of the x axis at 7 km / h with respect to the ground.

This causes the speed of the boat relative to the ground to be calculated as follows:

VbG = Vbw - VwG

where VbG is the speed of the boat relative to the ground, Vbw is the speed of the boat relative to the water of the river and VwG is the speed of the water relative to the ground.

So: VbG=10 km/h – 7 km/h

VbG= 3 km/h

The direction of this velocity is in the positive x-direction.

4 0

2 years ago

During which month is the bacteria population just under 1 million?

Thepotemich [5.8K]

D. March because it is just below the 1 million marker on the graph and it is the only one that low.

5 0

2 years ago

Normalize the equations

tatyana61 [14]

Answer:

Solution is in explanation

Explanation:

part a)

For normalization we have

$\int_{0}^{\infty }f(x)dx=1\\\\\therefore \int_{0}^{\infty }ae^{-kx}dx=1\\\\\Rightarrow a\int_{0}^{\infty }e^{-kx}dx=1\\\\\frac{a}{-k}[\frac{1}{e^{kx}}]_{0}^{\infty }=1\\\\\frac{a}{-k}[0-1]=1\\\\\therefore a=k$

Part b)

$\int_{0}^{L }f(x)dx=1\\\\\therefore Re(\int_{0}^{L }ae^{-ikx}dx)=1\\\\\Rightarrow Re(a\int_{0}^{L }e^{-ikx}dx)=1\\\\\therefore Re(\frac{a}{-ik}[\frac{1}{e^{ikx}}]_{0}^{L})=1\\\\\Rightarrow Re(\frac{a}{-ik}(e^{-ikL}-1))=1\\\\\frac{a}{k}Re(\frac{1}{-i}(cos(-kL)+isin(-kL)-1))=1$

$\frac{a}{k}Re(\frac{1}{-i}(cos(-kL)+isin(-kL)-1))=1\\\\\frac{a}{k}Re(icos(-kL)+sin(kL)+\frac{1}{i})=1\\\\\frac{a}{k}sin(kL)=1\\\\a=\frac{k}{sin(kL)}$

7 0

3 years ago

In a series of undisturbed rock layers where shale lies between sandstone below and limestone above, the ____.

larisa86 [58]

The answer to the question 'In a series of undisturbed rock layers where shale lies between sandstone below and limestone above, the __." would be limestone is youngest. Out of all the rock layers, the limestone is dated to be the youngest of all.

8 0

3 years ago

Read 2 more answers

Unpolarized light with intensity S is incident on a series of polarizing sheets. The first sheet has its transmission axis orien

jeka94

Answer:

Explanation:

Given

Initial Intensity of light is S

when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.

When it is passed through a second Polarizer with its transmission axis $\theat =45^{\circ}$