Answer:
q = 0.036 C
Explanation:
Given that,
Current passes through a defibrillator, I = 18 A
Time, t = 2 ms
We need to find the charge moved during this time. We know that,
Electric current = charge/time

Put all the values,

So, 0.036 C of charge moves during this time.
Answer:
C. a small charged particle.
Explanation:
typically beta radiation emits an electron which is a small negativity charged particle.
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Noise does not affect the digital signal making it more reliable
Answer:
Q = - 256 X 10⁻⁷ C .
Explanation:
Electric field due to a charge Q at a distance d from the center is given by the expression
E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹
Put the given value in the equation
9 x 10² = 
Q = 
Q = - 256 X 10⁻⁷ C .
It will be negative in nature as the field is directed towards the center.
The transfer of thermal energy as heat requires a difference in temperature between the two points of transfer. Heat may be transferred by means of conduction, convection, or radiation. Conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object.