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Klio2033 [76]
3 years ago
12

Name 3 objects that have gravitational potential energy?

Physics
1 answer:
dezoksy [38]3 years ago
6 0
Well i have three things that depends on potiential energy
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Please helppppppp!!!!!!!!!!!!!!!!!!!!!!!!
kykrilka [37]

Answer:

I think the Bulb No. 2 will stop emitting light if the bulb No. 1 burns out.

3 0
3 years ago
The electric field of a sinusoidal electromagnetic wave obeys the equation E = (375V /m) cos[(1.99× 107rad/m)x + (5.97 × 1015rad
kenny6666 [7]

Answer:

a)  v = 2,9992 10⁸ m / s , b)  Eo = 375 V / m ,  B = 1.25 10⁻⁶ T,

c)     λ = 3,157 10⁻⁷ m,   f = 9.50 10¹⁴ Hz ,  T = 1.05 10⁻¹⁵ s , UV

Explanation:

In this problem they give us the equation of the traveling wave

        E = 375 cos [1.99 10⁷ x + 5.97 10¹⁵ t]

a) what the wave velocity

all waves must meet

        v = λ f

In this case, because of an electromagnetic wave, the speed must be the speed of light.

        k = 2π / λ

        λ = 2π / k

        λ = 2π / 1.99 10⁷

        λ = 3,157 10⁻⁷ m

        w = 2π f

        f = w / 2 π

        f = 5.97 10¹⁵ / 2π

        f = 9.50 10¹⁴ Hz

the wave speed is

        v = 3,157 10⁻⁷   9.50 10¹⁴

        v = 2,9992 10⁸ m / s

b) The electric field is

           Eo = 375 V / m

to find the magnetic field we use

           E / B = c

           B = E / c

            B = 375 / 2,9992 10⁸

            B = 1.25 10⁻⁶ T

c) The period is

           T = 1 / f

            T = 1 / 9.50 10¹⁴

            T = 1.05 10⁻¹⁵ s

the wavelength value is

          λ = 3,157 10-7 m (109 nm / 1m) = 315.7 nm

this wavelength corresponds to the ultraviolet

5 0
4 years ago
What is the voltage of the electrochemical cell written as: Cu(s) | Cu2+(aq) || Mg2+(aq) | Mg(s)?
erma4kov [3.2K]
Thank you for posting your question here at brainly. Feel free to ask more questions.  
<span><span>The best and most correct answer among the choices provided by the question is  </span>B.-2.71 V.</span>  
Mg2+(aq) + 2e- -> Mg(s) E=-2.37 V  

Cu2+(aq) + 2e- -> Cu(s) E =+ 0.34 V  

Since Cu is acting as the anode, the equation needs to be reversed.  

Cu(s) -> Cu2+(aq) + 2e- E =- 0.34 V  

Ecell= -2.37 V+ (- 0.34 V) = -2.71 V   <span><span>

</span><span>Hope my answer would be a great help for you. </span> </span> <span> </span>
4 0
4 years ago
A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i
Hoochie [10]

The acceleration of the box is approximately 1 m/s^2

Explanation:

According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:

\sum F = ma

where

\sum F is the net force

m = 12.0 kg is the mass of the box

a is the acceleration

The net force can be written as

\sum F = F_a - F_f

where

F_a = 20 N is the applied forward force

F_f=9.0 N is the friction force

Combining the two equations,

F_a-F_f=ma

And solving for the acceleration,

a=\frac{F_a-F_f}{m}=\frac{20-9}{12}=0.9 m/s^2\sim 1 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
A ruby laser delivers a 16.0-ns pulse of 4.20-MW average power. If the photons have a wavelength of 694.3 nm, how many are conta
stepan [7]

Answer:

The  value is  n  =  2.347 *10^{17} \  photons

Explanation:

From the question we are told that

     The  amount of power delivered is  P  =  4.20 \  M W  =  4.20  *10^{6} \  W

      The  time taken is  t =  16.0ns  =  16.0 *10^{-9} \  s

       The  wavelength is  \lambda  =  694.3 \  nm =  694.3 *10^{-9} \  m

     

Generally the energy delivered is  mathematically represented as

     E  =  P  * t  =  \frac{n  *  h  *  c  }{\lambda }

Where  h is the Planck's constant with value  h  =  6.262  *10^{-34} \  J \cdot  s

           c  is the speed of light with value  c =  3.0*10^{8} \  m/s

     

So  

    4.20 *10^{6}  *  16*10^{-9}=  \frac{n  *  6.626 *10^{-34}  *  3.0*10^{8}  }{694.3 *10^{-9}}

=>    n  =  2.347 *10^{17} \  photons

4 0
3 years ago
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