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The correct answer to your question is: Spectrum
A spectrum, by definition, is a range of colors which are produced by separating certain colors of light.
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Answer:
If 51.8 of Pb is reacting, it will require 4.00 g of O2
If 51.8 g of PbO is formed, it will require 3.47 g of O2.
Explanation:
Equation of the reaction:
2 Pb + O2 → 2 PbO
From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO
Molar mass of Pb = 207 g
Molar mass of O2 = 32 g
Molar mass of PbO = 207 + 32 = 239 g
Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO
= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO
Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.
If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2
Answer:
1.- Chemical change
2.- Because the atoms in the image are tranformed into a new molecule
3.- Yes, it does
4.- Due to the amount of atoms are the same both in products and reagents
Explanation:
Answer:
Dipole-dipole interactions
Step-by-step explanation:
Each molecule consists of <em>two different elements</em>.
Thus, each molecule has permanent <em>bond dipoles</em>.
The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.
"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.
There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.
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