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Georgia [21]
3 years ago
14

How many grams of water are needed to react with 18.9 grams of li2o? given: li2o+h2oâ2lioh?

Chemistry
1 answer:
4vir4ik [10]3 years ago
4 0
The balanced equation for the reaction is as follows;
Li₂O + H₂O ---> 2LiOH
Stoichiometry of Li₂O to H₂O is 1:1
Mass of Li₂O reacted - 18.9 g
Number of Li₂O moles reacted - 18.9 g / 30 g/mol = 0.63 mol
An equivalent amount of moles of water have reacted - 0.63 mol
mass of water required - 0.63 mol x 18 g/mol = 11.34 g
A mass of 11.34 g of water is required 
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3 years ago
In the presence of oxygen, the three-carbon compound pyruvate can be catabolized in the citric acid cycle. First, however, the p
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Answer:1.

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6 0
3 years ago
A rock sample from the moon includes a mineral that contains small amounts of the radioactive isotope Potassium-40 and its daugh
Simora [160]

Answer:

There were originally 8 atoms of Potassium-40.

Explanation:

The half-life of a radioactive material is the time taken for half the original material to decay or the time required for a quantity of the radioactive substance to reduce to half of its initial value.

If the original material formed without any Argon-40, it means that the atoms originally present were Potassium-40 atoms.

Presently, there are 7 Argon-40 atoms for every 1 of Potassium-40, we can deduce the number of half-lifes the Potassium-40 has undergone as follows :

After one half-life, (1/2) there will be one Potassium-40 atom for every Argon-40 atom.

After a second half life, 1/2 × 1/2 = 1/4: there will be one Potassium-40 atom for every three atoms of Argon-40.

After a third half-life, 1/4 × 1/2 = 1/8: there will be one Potassium-40 atom for every 7 atoms of Argon-40.

Since there are 1/8 atoms of Potassium-40 presently, there were originally 8 atoms of Potassium-40.

6 0
3 years ago
What is the % by volume of 50mL of ethylene glycol dissolved in 950mL of H2O?
MariettaO [177]

Answer:

5.0 %

Explanation:

Given data

  • Volume of ethylene glycol (solute): 50 mL
  • Volume of water (solvent): 950 mL

Step 1: Calculate the volume of solution

If we assume that <em>the volumes are additive</em>, the volume of the solution is equal to the sum of the volume of the solute and the solvent.

V = 50 mL + 950 mL = 1000 mL

Step 2: Calculate the percent by volume

We will use the following expression.

\% v/v = \frac{volume\ of\ solute}{volume\ of\ solution} \times 100 \%  = \frac{50mL}{1000mL} \times 100 \% = 5.0\%

5 0
3 years ago
Suppose protons were emitted rather than electrons. How would this affect the experiment?
Vera_Pavlovna [14]

Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .

The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects.  We can conserve the electric energy which is equal to the qe .

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The mean velocity of proton will be less then mean velocity electron .

To learn more about proton

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2 years ago
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