I think this is the answer
Answer:
Bromine is found in Group 17, Period 4 on the periodic table.
Answer:
initial temperature=![-3.31^{\circ}C](https://tex.z-dn.net/?f=-3.31%5E%7B%5Ccirc%7DC)
Explanation:
Assuming that the given follows the ideal gas nature;
![P_1=0.723atm](https://tex.z-dn.net/?f=P_1%3D0.723atm)
![V_1=13.5L](https://tex.z-dn.net/?f=V_1%3D13.5L)
![T_1=?](https://tex.z-dn.net/?f=T_1%3D%3F)
![P_2=0.612atm](https://tex.z-dn.net/?f=P_2%3D0.612atm)
![V_2=17.8L](https://tex.z-dn.net/?f=V_2%3D17.8L)
![T_2=28 ^{\circ}C =273+28K=301K](https://tex.z-dn.net/?f=T_2%3D28%20%5E%7B%5Ccirc%7DC%20%3D273%2B28K%3D301K)
mole of gass will remain same at any emperature:
![\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%20%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
putting all the value we get:
![T_2 =269.7K =-3.31 ^{\circ} C](https://tex.z-dn.net/?f=T_2%20%3D269.7K%20%3D-3.31%20%5E%7B%5Ccirc%7D%20C)
initial temperature=![-3.31^{\circ}C](https://tex.z-dn.net/?f=-3.31%5E%7B%5Ccirc%7DC)
Answer: 4.12
Explanation:
we know that the given mol is 8.23 mol and they are 2NaI and I2 so we will write the equation like this.
8.23mol NaI x 1mol of I2 ÷ 2molNaI = 4.115≅ 4.12 mol of I2
we placed NaI at the bottom to cancel out with the 8.23 mol of NaI
A. Amount of sleep, since it depends on how much coffee she drinks