- The substance that made up of a particular mixture can be regarded as Solute and solvent
- A mixture can be regarded as material which is made up of more than one different Chemical substance or substances , whereby they are not chemically combined.
- Substance could be any matter such as <em>salt, rice, and or compounds</em>
- A mixture can be regarded as physical combination involving two or more substances whereby each entities identities are retained, then mixed in the form such as ;
- <em>solutions</em>
- <em> suspensions </em>
- <em> colloids</em>.
- A mixture could be in this form <em>(Solute + solvent = solution)</em>
Therefore, the substance that made up of a particular mixture can be regarded as <em>Solute and solvent</em>
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Answer:

Explanation:
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In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

Thus, we first need to compute the molality of each solute, as shown below:

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.
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Answer:
Absorb light energy
Explanation:
Chlorophyll absorbs light energy which is used to produce carbohydrate and oxygen in the presence of carbon dioxide and water.
(The other are Jupiter, Saturn,and Neptune)It's atmosphere is composed primarily of hydrogen and helium with a small amount of methane and traces of water in an ammonia Uranus gets its blue green color from methane gas.
sunlight is reflected from Uranus's clould tops, which lie beneath a layer of methane gas Uranus is clouds top with lie beneath a layer of methanol gas
Answer:
-65.897°C.
Explanation:
- Adding solute to water causes depression of the boiling point.
- The depression in freezing point (ΔTf) can be calculated using the relation: <em>ΔTf = Kf.m,</em>
where, ΔTf is the depression in freezing point of chloroform solution.
Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).
m is the molality of the solution (m = 0.51 m).
∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.
∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.