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ivann1987 [24]
3 years ago
5

Some elements are more "reactive" than other elements; why do you think this is?

Chemistry
2 answers:
Andreas93 [3]3 years ago
8 0

Answer:

The reactivity of any element depends on its valence electrons, its atomic radius and its electronegativity.

Explanation:

Valence electrons are electrons occupying the outer shell of the atom. Therefore they're responsible for all of chemical properties and some of the physical properties of the element. They determine the number of bonds the atom can form. For instance, the carbon atom has four valence electrons. Thus, any carbon atom can form four covalent bonds with surrounding atoms. On the other hand, hydrogen atoms, which have only one valence electron, can only form one covalent bond.

The atomic radius, defined as half the distance between the nuclei of two adjacent atoms, affects reactivity as well. The smaller the radius, the more reactive the element is. For example, it is possible compare the reactivity of Fluorine to the one of Iodine. The first is smaller than Iodine, which means that the electron's cloud allows the fluorine nucleus to attract more strongly the outer electrons: both its own and the electrons of other atoms.  

These two previous properties combined give place to a third one: electronegativity. Which is a measure of the tendency ot the atoms in molecules to attract electrons to themselves.

In general, an element with small atoms has more electronegativity than a big one.

Additionally some elements having big atoms (and thus with low electronegativity) are said to be very reactive too because of their tendency to lose easily their valence electrons (i.e., Francium).

Ket [755]3 years ago
3 0

All other atoms have less stable electron numbers, so they react with each other and share electrons to be more stable. The most reactive elements tend to be short one or two electron or have one or two extra.


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What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm
lesya [120]

<u>Answer:</u> The mass of sucrose required is 69.08 g

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL    (Density of water = 1 g/mL)

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g

Hence, the mass of sucrose required is 69.08 g

5 0
3 years ago
At 10C, 100g of H2O can dissolve only 78g of NaNO3
mamaluj [8]

Answer:

The given parameter for the solubility of NaNO₃ in H₂O are;

The maximum solubility of NaNO₃ in H₂O at 10°C = 78 g

1. If we have 50 g of NaNO₃ in 100 g of water at 10°C, the solution is;

Undersaturated

2. If we have exactly 78 g of NaNO₃ in 100 g of water at 10°C the solution is;

A saturated solution

3. If will add 80 g of NaNO₃ in 100 g of water at 10°C,

The excess NaNO₃ which cannot be dissolved will be observed as solids in the mixture

4) The quantity of NaNO₃ that can be dissolved in H₂O at 40°C = 94 g

If the solution containing 94 g of NaNO₃ at 40°C is cooled to 10C about 16 g of NaNO₃ will precipitate out of the solution and exist as solids in the mixture

Explanation:

1. An undersaturated is a solution that holds smaller amount of solute that it can hold at a given temperature

2. A saturated solution holds as much solute as it can dissolve at a given temperature

3. When more solutes are added to a saturated solution, the excess solution will remain in the solid form in the mixture

4) Cooling a saturated solution below the saturation temperature will result in the precipitation or crystallization of the excess solutes in the solution.

6 0
3 years ago
How long will a current of 0.995 A need to be passed through water (containing H2SO4) for 5.00 L of O2 to be produced at STP
DIA [1.3K]

Answer:

24 hours

Explanation:

The computation is shown below:

The needed mole of O_2 is

= 5 ÷22.4 = n

Also 1 mole of O_2 required four electric charge

Now the charge needed is

= n × 4 × 96,500 C

= 4 × 96,500 × 5 c ÷ 22.4

= 86160.714 C

Now

q = i t

t = q ÷ i

= 86160.714 C ÷ 0.995

= 86593.7 seconds

= 24 hours

Hence, the correct option is A.

3 0
3 years ago
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