It would be 5 ML of chloride dissovled
I believe the answer is A the 1st one
The answer is 12.5 mL.
Solution:
<u>M, 6.00M V₁ =?</u>
M2 = 3.00M, V₂ = 25.0mL
<u>M1V1 = M2 V2/M1</u>
V1 = M2V2 M,
V1 = 25.0X3.00/6.00
∴ V1 = 12.5 mL
The initial concentration of the resulting solution is 2 molar which is the volume multiplied by the concentration. The volume of the starting solution is therefore 2,500 ml × 2.25 mol. Calculate the number of moles of HCl dissolved in a given volume of acid by reacting an acid with CaCO3.
This is essentially a double exchange reaction with the decomposition of one of the products. To determine the amount of stock solution required divide the number of moles of glucose by the molarity of the stock solution.
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