Question

How long will a current of 0.995 A need to be passed through water (containing H2SO4) for 5.00 L of O2 to be produced at STP

Answer 1

Answer:

24 hours

Explanation:

The computation is shown below:

The needed mole of $O_2$ is

= 5 ÷22.4 = n

Also 1 mole of $O_2$ required four electric charge

Now the charge needed is

= n × 4 × 96,500 C

= 4 × 96,500 × 5 c ÷ 22.4

= 86160.714 C

Now

q = i t

t = q ÷ i

= 86160.714 C ÷ 0.995

= 86593.7 seconds

= 24 hours

Hence, the correct option is A.