How long will a current of 0.995 A need to be passed through water (containing H2SO4) for 5.00 L of O2 to be produced at STP
1 answer:
Answer:
24 hours
Explanation:
The computation is shown below:
The needed mole of is
= 5 ÷22.4 = n
Also 1 mole of required four electric charge
Now the charge needed is
= n × 4 × 96,500 C
= 4 × 96,500 × 5 c ÷ 22.4
= 86160.714 C
Now
q = i t
t = q ÷ i
= 86160.714 C ÷ 0.995
= 86593.7 seconds
= 24 hours
Hence, the correct option is A.
You might be interested in
Answer:
Explanation:
The number of valence electrons tells us the group number of the neutral atom.
The atom has 4 valence electrons.
The atom is in group 4.
Answer:
Explanation:
Hello,
In this case, weak acids are characterized by the fact they do not dissociate completely, it means they do not divide into the conjugated base and acid at all, a percent only, which is quantified via equilibrium. In such a way, the chemical equation representing such incomplete dissociation is said to be:
Thus, we can write the law of mass action, which consider the equilibrium concentrations of all the involved species, which is also known as the acid dissociation constant which accounts for the capacity the acid has to yield hydronium ions:
Best regards.