All categories

3 years ago

What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?

Physics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:

The acceleration of the proton is 9.353 x 10⁸ m/s²

Explanation:

Given;

speed of the proton, u = 6.5 m/s

magnetic field strength, B = 1.5 T

The force of the proton is given by;

F = ma = qvB(sin90°)

ma = qvB

where;

m is mass of the proton, = 1.67 x 10⁻²⁷ kg

charge of the proton, q = 1.602 x 10⁻¹⁹ C

The acceleration of the proton is given by;

$a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2$

Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²

You might be interested in

The law of conservation of momentum states that the total momentum of interacting objects does not change . This means the total

pickupchik [31]

Answer:

The momentum of an object is equal to the product of its mass and its velocity.

Explanation:

Consider an object of mass $m$ travelling at a velocity $\vec{v}$ . The momentum $\vec{p}$ of this object would be:

$\vec{p} = m \cdot \vec{v}$ .

For the law of conservation of momentum, consider two objects: object $\rm a$ and object $\rm b$ . Assume that these two objects collided with each other.

Let $m_{\rm a}$ and $m_{\rm b}$ denote the mass of the two objects.
Let $\vec{v}_{\rm a}(\text{initial})$ and $\vec{v}_{\rm b}(\text{initial})$ denote the velocity of the two object right before the interaction.
Let $\vec{v}_{\rm a}(\text{final})$ and $\vec{v}_{\rm b}(\text{final})$ denote the velocity of the two objects right after the interaction.

The momentum of the two objects right before the collision would be $m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial})$ and $m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})$ , respectively.
The momentum of the two objects right after the collision would be $m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final})$ and $m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})$ , respectively.

The sum of the momentum of the two objects would be:

$m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})$ right before the collision, and
$m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})$ right after the collision.

Assume that the system of these two objects is isolated. By the law of conservation of momentum, the sum of the momentum of these two objects should be the same before and after the collision. That is:

$m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) = m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})$ .

4 0

4 years ago

A 1.5V battery is connected to a small light bulb with a resistance of 3.5 what is the current in the bulb?

notka56 [123]

Technically, we don't have the information needed to calculate the current,
because you haven't mentioned the units of the 3.5 .

Since the 3.5 is a resistance, we strongly suspect ... and we'll therefore
assume ... that the 3.5 has the units of ohms. Then . . .

Current = (voltage) / (resistance) = (1.5/3.5) = <em>3/7 of an Ampere</em>.

(429 mA, rounded)

5 0

3 years ago

Any of two or more forms of the same element which differ only in the number of neutrons their atoms contain is called an

telo118 [61]

C. isotope

Isotopes have the same atomic number but different mass number because of the difference in the number of neutrons in the nucleus of the atom.

8 0

3 years ago

Compare the forces if the light truck is standing still when the car hits it. 1. The car exerts a greater amount of force on the

denis23 [38]

Answer:

Only 3 is true: The truck exerts the same amount of force on the car as the car exerts on the truck.

Explanation:

Compare the forces if the light truck is standing still when the car hits it.

1. The car exerts a greater amount of force on the truck than the truck exerts on the car. FALSE. This violates Newton 3rd Law of Action-Reaction.

2. The truck exerts a greater amount of force on the car than the car exerts on the truck. FALSE. This violates Newton 3rd Law of Action-Reaction.

3. The truck exerts the same amount of force on the car as the car exerts on the truck. TRUE. This is Newton 3rd Law of Action-Reaction. When there is a contact between objects, both exert on the other an equal and opposite force.

4. None of the answers correctly describes the situation. FALSE. 4 is true.

5. Neither exerts a force on the other. FALSE. If the car hits it then forces must come into play.

5 0

3 years ago

Two very small +3.00-μC charges are at the ends of a meter stick. Find the electric potential (relative to infinity) at the cent

PtichkaEL [24]

Answer:

The electric potential at the center of the meter stick is 54 KV.

Explanation:

Electric potential (V) is given as:

i.e V = $\frac{kq}{r}$