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vichka [17]
3 years ago
14

What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?

Physics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

The acceleration of the proton is 9.353 x 10⁸ m/s²

Explanation:

Given;

speed of the proton, u =  6.5 m/s

magnetic field strength, B = 1.5 T

The force of the proton is given by;

F = ma = qvB(sin90°)

ma = qvB

where;

m is mass of the proton, = 1.67 x 10⁻²⁷ kg

charge of the proton, q = 1.602 x 10⁻¹⁹ C

The acceleration of the proton is given by;

a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2

Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²

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Given Information:

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Answer:

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Explanation:

The time constant is given by

τ = RC

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C = kεoA/L

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Therefore, the time constant is

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τ = 6.45×10⁷*44.5×10⁻¹²

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