Answer:
The resulting magnetic force on the wire is -1.2kN
Explanation:
The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is
F = I (L*B)
Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)
L x B = ![\left[\begin{array}{ccc}i&j&k\\2&0&0\\30&-40&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C2%260%260%5C%5C30%26-40%260%5Cend%7Barray%7D%5Cright%5D)
= (0, 0, -80)
we can now solve
F = I (L x B) = I (-80)
F = -1200 kmN
F = -1200 kN * 10⁻³
F = -1.2kN
Answer:
i = 0.5 A
Explanation:
As we know that magnetic flux is given as
here we know that
N = number of turns
B = magnetic field
A = area of the loop
now we know that rate of change in magnetic flux will induce EMF in the coil
so we have
now plug in all values to find induced EMF
now by ohm's law we have
Hello there.
<span>In the context of depth perception, which of the following is a monocular cue?
</span><span>(C) Convergence
</span>
Single
Displacement Reaction Definition. A
single displacement reaction is a chemical reaction where one reactant is exchanged for one ion of a second reactant. It is also known as a
single replacement reaction.
The answer is a) Teres Major Muscle
