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katen-ka-za [31]
3 years ago
15

a Stone is dropped into a deep well and is heard to hit the water 3.41s after being dropped. determine the depth of the well

Physics
1 answer:
tangare [24]3 years ago
5 0
Using SUVAT

U = 0 m/s
A = g = 9.8 ms^-2
T = 3.41 s
S = ?

s = ut + 1/2at^2
s = (0)(3.41) + 1/2(9.8)(3.41^)
s = 1/2(9.8)(3.41^2)
s = 1/2(9.8)(11.6281)
s = 56.97769 m
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  • In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:

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