a Stone is dropped into a deep well and is heard to hit the water 3.41s after being dropped. determine the depth of the well

1 answer:

5 0

Using SUVAT

U = 0 m/s
A = g = 9.8 ms^-2
T = 3.41 s
S = ?

s = ut + 1/2at^2
s = (0)(3.41) + 1/2(9.8)(3.41^)
s = 1/2(9.8)(3.41^2)
s = 1/2(9.8)(11.6281)
s = 56.97769 m

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