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larisa [96]
3 years ago
8

A chemist dissolved crystals of an unknown substance into water at room temperature. He found that 33 g of the substance can be

dissolved into 100ml of water. What property of the unknown substance was the chemist most likely investigating?
Chemistry
1 answer:
Radda [10]3 years ago
7 0
The property that the scientist was most likely investigating was the solubility of the crystals. 
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How many atoms of carbon are in 6.00g of carbon?(Mm of carbon is<br> 12g/mol)
xenn [34]
<h3>Answer:</h3>

3.01 × 10²³ atoms C

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

6.00 g C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

<u />6.00 \ g \ C(\frac{1 \ mol \ C}{12.01 \ g \ C} )(\frac{6.022 \cdot 10^{23} \ atoms \ C}{1 \ mol \ C} ) = 3.00849 × 10²³ atoms C

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.00849 × 10²³ atoms C ≈ 3.01 × 10²³ atoms C

5 0
3 years ago
Need help with this science question............
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Answer:

18- H

19- D

20-G

21-A

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Explanation:

4 0
2 years ago
A chemical reaction in which one element replaces another element in a compound can be categorized as?
alexira [117]
Replacement reaction
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Stuck stupid science homework. anyone know answers?
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How many moles are in 213 grams of NaCl?
Nata [24]

Answer:

There are 3, 64 moles of NaCl.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol

58,5 g ------1 mol NaCl

213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>

5 0
3 years ago
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