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zhannawk [14.2K]
3 years ago
12

Jonah finds a rusty nail outside. The nail is an example of _____.

Physics
2 answers:
Aleonysh [2.5K]3 years ago
7 0

Answer: Option (A) is the correct answer.

Explanation:

When metal is corroded due to moist air then this process is known as rusting of iron.  

When a nail rusts then it represents that metal has turned into metal oxide. This means that chemical composition of substance has changed.

Thus, we can conclude that Jonah finds a rusty nail outside. The nail is an example of chemical weathering.

Pani-rosa [81]3 years ago
3 0
I believe the correct answer from the choices listed above is option A. Jonah finds a rusty nail outside. The nail is an example of <span>chemical weathering. Rusting of nail is a result of reaction of iron with water in air. Hope this answers the question. Have a nice day.</span>
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Assume that the driver begins to brake the car when the distance to the wall is d=107m, and take the car's mass as m-1400kg, its
Evgen [1.6K]

Answer:

Explanation:

a ) Let let the frictional force needed be F

Work done by frictional force = kinetic energy of car

F x 107 = 1/2 x 1400 x 35²

F = 8014 N

b )

maximum possible static friction

= μ mg

where μ is coefficient of static friction

= .5 x 1400 x 9.8

= 6860 N

c )

work done by friction for μ = .4

= .4 x 1400 x 9.8 x 107

= 587216 J

Initial Kinetic energy

= .5 x 1400 x 35 x 35

= 857500 J

Kinetic energy at the at of collision

= 857500 - 587216

= 270284 J

So , if v be the velocity at the time of collision

1/2 mv² = 270284

v = 19.65 m /s

d ) centripetal force required

= mv₀² / d which will be provided by frictional force

= (1400 x 35 x 35) / 107

= 16028 N

Maximum frictional force possible

= μmg

= .5 x 1400 x 9.8

= 6860 N

So this is not possible.

4 0
3 years ago
Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an
SpyIntel [72]

Answer:

a) 2.43 m/s

b) 4.83 m/s

c) 0.023 m/s²

Explanation:

a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration

Speed = Distance / Time

\text{Speed}=\frac{510}{210}=2.43\ m/s

Velocity of car A is 2.43 m/s

t = Time taken = 210 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 510 m

a = Acceleration

c)

s=ut+\frac{1}{2}at^2\\\Rightarrow 510=0\times 210+\frac{1}{2}\times a\times 210^2\\\Rightarrow a=\frac{510\times 2}{210^2}\\\Rightarrow a=0.023\ m/s^2

Acceleration of car B is 0.023 m/s²

b)

v=u+at\\\Rightarrow v=0+0.023\times 210\\\Rightarrow v=4.83\ m/s

Final velocity of car B is 4.83 m/s

6 0
3 years ago
Is Time and Light both connected in anyway?​
MissTica

Answer:

It is not connected by any way

8 0
2 years ago
Metals combine easily with nonmetals. true or false
Ad libitum [116K]
The answer for that is True.
4 0
2 years ago
Assignment 10 Coulombic Equation Practice Directions: Complete the following problems to calculate the electrostatic force that
Tatiana [17]

Answer:

Magnitude of the force between the charges is F = 1.92×10^20N

Explanation:

Given the magnitude of force according to coulombs law

F =K[(q1*q2)/r2]

Where q1 and q2 are the charges

r is the distance between the charges

K is the coulombs constant

Substituting the given values, we have;

F = 8.98×10^9 × 1.5×10^6 × 3.2×10^4/1.5²

F = 43.1×10^19/2.25

F = 19.16×10^19N

F = 1.92×10^20N

8 0
3 years ago
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