7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J
8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m
9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333
<u>Answer:</u>
Work input = Work output * Work against friction is your answer so C
<u>Explanation:</u>
I hope this helps you :)
Step 1: list known info
distance(change in position (Δx))= 18m+22m= 40m
time= 20 seconds
Step 2 :solve for velocity
velocity= Δx÷time
v= 40/20= 2m/s
Answer: the velocity is 2 meters per a second (m/s)
Answer: mechanical energy
Explanation: I hope this helps! Also, please mark as brainliest, thanks!