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ELEN [110]
3 years ago
9

Most metallic elements, such as copper

Physics
1 answer:
nata0808 [166]3 years ago
5 0

Answer:

G. it enables people to use pots and pans made of metal to cook food

Explanation:

Metals are known to be substances with a relative high melting point, which means that it takes a very high temperature to melt them. As used in this question, copper (Cu) and iron (Fe) at metallic elements that have high melting points.

One advantage of this property based on the options provided is that "it enables people to use pots and pans made of metal to cook food". This is because cooking food requires subjecting them to a constant temperature from a heat source e.g cooker or stove.

The material used to hold the food being cooked must possess a very high melting point to withstand the heat, hence, the importance of these metallic substances. Most pots and pans are made of steel, an alloy of iron, hence, they have high melting point.

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A gry is an old English measure for length, defined as 1/10 of a line, where line is another old English measure for length, def
Rashid [163]

Answer:

0.0576 points²

Explanation:

1\ gry=\frac{1}{10}\ line

1\ line=\frac{1}{12}\ inch

\frac{1}{10}\ line=\frac{1}{10}\times \frac{1}{12}\ inch\\\Rightarrow \frac{1}{10}\ line=\frac{1}{120}\ inch

\therefore 1\ gry=\frac{1}{120}\ inch

1\ point=\frac{1}{72}\ inch\\\Rightarrow 72\ points=1\ inch

\\\Rightarrow \frac{1}{120}\ inch=\frac{1}{120}\times 72\ points

1\ gry=\frac{72}{120}\ point\\\Rightarrow 1\ gry=0.6\ point

0.16\ gry^2=0.6^2\times 0.16\\\Rightarrow 0.16\ gry^2=0.0576\ points^2

∴ Area of 0.16 gry² is 0.0576 points²

8 0
3 years ago
What are the constant parameters in Charles' gas law?
zepelin [54]
Charles's Law<span>, or the </span>law<span> of volumes, was found in 1787 by Jacques </span>Charles<span>. It states that, for a given mass of an </span>ideal gas<span> at </span>constant<span> pressure, the volume is directly proportional to its absolute temperature, assuming in a closed system. The constant parameters would be the number of moles and pressure.</span>
7 0
3 years ago
A 32.5 g cube of aluminum initially at 45.8 °C is submerged into 105.3 g of water at 15.4 °C. What is the final temperature of b
lbvjy [14]

Answer:

T = 17.26 ^oC

Explanation:

At thermal equilibrium we have heat given by aluminium must be equal to the heat absorbed by the water

so we will have

Q_1 = Q_2

m_1s_1\Delta T_1 = m_2s_2\Delta T_2

so we will have

32.5(900)(45.8 - T) = 105.3(4186)(T - 15.4)

so we have

(45.8 - T) = 15.1(T - 15.4)

so we have

16.1 T = 277.87

T = 17.26 ^oC

3 0
3 years ago
Gravity anything with mass as gravity we know the earth has gravity because you and I are standing on earth and not floating off
Paraphin [41]

Answer:

F=mg

Explanation:

Close to Earth's surface, the force of gravity that pulls an object towards the ground is

F=mg (2)

where

m is the mass of the object

g is the acceleration due to gravity, which is 9.81 m/s^2 close to Earth's surface

This is an approximation of the general formula of gravity valid only close to Earth's surface. The more general formula is

F=G\frac{Mm}{r^2} (1)

where

G is the gravitational constant

M is the Earth's mass

m is the object's mass

r is the distance of the object from Earth's center

At the Earth's surface,

r = R (Earth's radius), and by calling the following factor

g=\frac{GM}{R^2}

we see that eq.(1) becomes eq.(2).

8 0
3 years ago
Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. Wh
larisa [96]

Answer:

12.6332454263 m/s

Explanation:

m = Mass of car

v = Velocity of the car

\mu = Coefficient of static friction = 0.638

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of turn = 25.5 m

When the car is on the verge of sliding we have the force equation

\dfrac{mv^2}{r}=\mu mg\\\Rightarrow v=\sqrt{\mu gr}\\\Rightarrow v=\sqrt{0.638\times 9.81\times 25.5}\\\Rightarrow v=12.6332454263\ m/s

The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s

4 0
3 years ago
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