A)
Withdraws--5.23, -5.22, and -7.89
Deposits-34.98, 51.02, and 51.22
(Rational numbers include integers, whole numbers, decimals that don't repeat or go on forever, and fractions)
B)
-7.89, -5.23, -5.22, 34.98, 51.02, 51.22
(Negatives are less than 0, so when the negative gets bigger, it means that the number is becoming less, so the opposite of positive numbers)
C)
98+34.98+51.02+51.22= 235.22
235.22- 5.22-5.23-7.89= 216.88
216.88 is the answer
(since withdraws are subtracting from the total, you want to add up all of the positive numbers so the deposits plus the amount she had in the beginning, and then subtract the withdraws)
Hope this helps!
you should click the first and third box because in order to check if something is a function, we have to look at the circles on the left and no number can have two lines pointing to it. there can only be one line per number. that is how i remembered it when i was in algebra 1
Answer:
<h2><em><u>Option</u></em><em><u>:</u></em><em><u> </u></em><em><u>D</u></em></h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u>, </u></em>
7,625,750,263
<em><u>When</u></em><em><u> </u></em><em><u>estimated</u></em><em><u>, </u></em>
8,000,000,000
= 8 × 1,000,000,000
![= 8 \times {10}^{9}](https://tex.z-dn.net/?f=%20%3D%208%20%20%5Ctimes%20%20%7B10%7D%5E%7B9%7D%20)
Answer:
d
Step-by-step explanation:
This might be confusing for some people but if you want to find the asymptote y=2, it will be a horizontal line, going through the y-axis. And an x asymptote would be vertical, going through points on the x-axis. And bc the graph is a growth, it would start from the left of the graph ( closer to the origin (0,0) and keep increasing towards the positive numbers
<u><em>Answer:</em></u>The factored form is: (x-2)(x-4) = 0
<u><em>Explanation:</em></u>To factor an expression, we need to <u>get its solutions</u>.
<u>The standard form of the quadratic equation is:</u>
ax² + bx + c = 0
<u>The given equation is:</u>
x² - 6x + 8 = 0
<u>By comparison:</u>
a = 1
b = -6
c = 8
Now, to get the roots, we will substitute with the values of a, b and c in the quadratic formula shown in the attached image.
<u>This will give us:</u>
either x =
![\frac{6+ \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%2B%20%5Csqrt%7B%28-6%29%5E2-4%281%29%288%29%7D%20%7D%7B2%281%29%7D%20%3D%204)
This means that
the first factor is (x-4)
or x =
![\frac{6- \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 2](https://tex.z-dn.net/?f=%20%5Cfrac%7B6-%20%5Csqrt%7B%28-6%29%5E2-4%281%29%288%29%7D%20%7D%7B2%281%29%7D%20%3D%202)
This means that
the second factor is (x-2)
Based on the above, the factored form would be:
(x-4)(x-2) = 0
Hope this helps :)