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Svetradugi [14.3K]
3 years ago
13

Which is example of a physical change?

Physics
1 answer:
Xelga [282]3 years ago
8 0
The correct answer would be C) Grinding Pepper.
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Select the situations from the list in which mechanical energy is conserved. (A) A ball slides down a hill with friction. (B) An
slamgirl [31]

Answer:

B, D,E,F

Explanation:

Situations from the list in which mechanical energy is conserved.

Whenever there is friction there is always some loss of energy in the process and hence energy cannot be conserved.

- The Moon orbiting the Earth  (Total energy is remains the same)

- An ice skater gliding along the ice ( smooth surface no friction loss)

- A ball sliding down a friction less hill  ( again friction less process)

- A child swinging on a friction less swing, ignoring air resistance

5 0
4 years ago
Read 2 more answers
When this type of rock breaks, it breaks into layers. A. igneous B. sedimentary C. foliated D. nonfoliated
netineya [11]
I think its a......or b :3 srry if i didnt say one answer but at least i broke it down into two answers right?

3 0
4 years ago
Read 2 more answers
A 3.30 x 10-2-kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring const
avanturin [10]

Answer:

0.17547 m

Explanation:

m = Mass of block = 3.3\times 10^{-2}\ kg

v = Velocity of block = 10.8 m/s

k = Spring constant = 125 N/m

A = Amplitude

The kinetic energy of the system is conserved

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow \\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{3.3\times 10^{-2}\times 10.8^2}{125}}\\\Rightarrow A=0.17547\ m

The amplitude of the resulting simple harmonic motion is 0.17547 m

6 0
3 years ago
What acceleration will you give to a 24.5 kg
Ludmilka [50]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                   \boxed{F=ma}

                                                 <u>Δ   Being   Δ</u>

                                             F = Force = 78,3 N

                                            m = Mass = 24,5 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

\boxed{a=78,3\ N / 24,5\ kg}

⇒ Resolving

\boxed{a=3.19\ m/s^{2}}

Result:

The aceleration is <u>3,19 meters per second squared (m/s²)</u>

Good Luck!!

4 0
3 years ago
The orbiting of the moon around the Earth can be explained by
HACTEHA [7]
When talking about orbits, it would have to be a mixture of both A. and B. since Newton's first law, gravity plays a huge part in an orbit. However, the universal gravitation law also tells us the relationship between two massive objects in orbit. But to choose only one, it would have to be B. Newton's first law
3 0
4 years ago
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