Hello there!
The formula for Force is F = MA, or
Force = Mass x Acceleration
Well, since we have a rock falling in free fall, we can use the magical number 9.8 m/s^2 (also known as gravity). We have our value for force, 147N (Newtons).
So now, we have the value of our acceleration, A, and our value of the force, F, in our formula.
147 = 9.8M
To solve for M, we need to divide 147 by 9.8.
147/9.8 = 15
This means our Mass is 15 kg (remember your units!)
I hope this helps!
Period and frequency are mutual reciprocals.
Period = 1 / frequency .
Frequency = 1 / period
(Frequency) x (Period) = 1
Answer:
No one is right
Explanation:
John Case:
The function is defined between -1 and 1, So it is not possible obtain a value greater.
In addition, if you move the function cosine a T Value, and T is the Period, the function take the same value due to the cosine is a periodic function.
Larry case:
Is you have , the domain of this is [0,2].
it is equivalent to adding 1 to the domain of the , and its mean that the function , in general, is not greater than .
Momentum is always conserves in a collision, so 2460*130 + 1225*89 = total momentum. After the collision, you can treat the two vehicles as one mass and divide momentum by mass to obtain velocity. 428825/3685 = 116.37 km/hr. Closest answer is B
Answer:
C = 4,174 10³ V / m^{3/4}
, E = 7.19 10² / ∛x, E = 1.5 10³ N/C
Explanation:
For this exercise we can calculate the value of the constant and the electric field produced,
Let's start by calculating the value of the constant C
V = C
C = V / x^{4/3}
C = 220 / (11 10⁻²)^{4/3}
C = 4,174 10³ V / m^{3/4}
To calculate the electric field we use the expression
V = E dx
E = dx / V
E = ∫ dx / C x^{4/3}
E = 1 / C x^{-1/3} / (- 1/3)
E = 1 / C (-3 / x^{1/3})
We evaluate from the lower limit x = 0 E = E₀ = 0 to the upper limit x = x, E = E
E = 3 / C (0- (-1 / x^{1/3}))
E = 3 / 4,174 10³ (1 / x^{1/3})
E = 7.19 10² / ∛x
for x = 0.110 cm
E = 7.19 10² /∛0.11
E = 1.5 10³ N/C