Answer:
As light travels in a straight line at a constant speed, it's acceleration is <u>0 m/s²</u>.
There is no rate of change of speed, so there is no acceleration.
- <u>0 m/s²</u> is the right answer.
The point of contact the path difference is zero but one of the interfering ray is reflected so the effective path difference becomes λ/2 thus the condition of minimum intensity is created in the center.
Answer:
Part of the question is missing but here is the equation for the function;
Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.
Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3
Explanation:
What is applied is the principle of dimensional homogenuity
From the equation V = (1/3)zxt2.
- V has a dimension of [L/T]
- t has a dimension of [T]
- from the equation, make z the subject of the relation
- z = v/xt2 where 1/3 is treated as a constant
- Substituting into the equation for z
- z = L/T / L x T2
- the dimension for z = 1/T3 i.e 1/ T - raised to power 3
Answer:
R = 7 [amp]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance. In this way, we have the following equation.
V = I*R
where:
V = voltage = 49 [V] (units of volts)
I = current = 7 [amp] (amperes)
R = resistance [ohms]
Now clearing R.
R =V/I
R = 49/7
R = 7 [amp]
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