Answer:
It can do work on an object by moving it or changing it.
Explanation:
Brainliest?
Given that,
Distance, d = 10700 km
Time taken by the airplane to complete the destination, t = 12 hours
We need to find the speed of the airplane. It is equal to the total distance covered divided by total time taken. So,

We know that,
1 km = 1000 m
1 h = 3600 s
So,

So, the speed of the airplane is 891.66 km/h or 247.68 m/s.
the answer is (A) the movement of the magnet relative to the coil
Answer:
4.14 eV
Explanation:
f = 1.0 ×10^15 Hz
h= 6.63×10^-34 J s ( this is called PLANCK 'S CONSTANT)
ENEGY = E = ?
E = hf ( THIS IS FORMULA FOR ENERGY OF ONE QUANTA OR ONE PHOTON )
E= 6.63×10^-34×1.0 ×10^15
E = 6.63×10^-19 J
As 1eV = 1.6×10^-19 J so changing energy in eV from joules we will divide energy by 1.6×10^-19
hence E in eV = 6.63×10^-19/(1.6×10^-19)
E = 4.14 eV
Answer:
The focal length of a lens is refers to the distance from the center of the lens to the principal foci.