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Sergeeva-Olga [200]
3 years ago
13

How does uncertainty relate to measurements and calculations made during an investigation?

Physics
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

Explanation :Uncertainty in measurements and calculations means difference between actual and measured data. We can say that all measurements have some degree of uncertainty. It can be of two types-1. Systematic error (because of error in measuring instrument) 2. Random error (human errors such as- delay in starting, delay in stopping).

Systematic errors are consistent in magnitude and direction so they can be easily removed by additive or proportional corrections while random errors vary in magnitude and direction and can not be easily removed.

DerKrebs [107]3 years ago
4 0
Uncertainty means that your result may be very random, so you can't trust the first or second or so observation, making several samples critical for accuracy. <span />
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A figure skater skates across a rink of length 50 m in 12.1 seconds. a. What is the average speed of the skater? (2 points) b. I
melamori03 [73]
(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
v= \frac{S}{t}= \frac{50 m}{12.1 s}=4.13 m/s

(b) The initial speed of the skater is
v_i = 4 m/s
while the final speed is
v_f = 5.3 m/s
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
a= \frac{v_f - v_i}{t}= \frac{5.3 m/s-4.0 m/s}{2.0 s}=0.65 m/s^2

(c) The initial speed of the skater is 
v_i = 13.0 m/s
while the final speed is 
v_f=0
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
2aS=v_f^2 -v_i^2
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a= \frac{-v_i^2}{2S}= \frac{-(13.0m/s)^2}{2 \cdot 8.0 m}=-10.6 m/s^2
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If a melon has a a mass of 1 kg, how much does the melon weigh?
My name is Ann [436]

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uysha [10]

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I need it in the next hour or so!
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The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is

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Solve for F[air] :

F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)

F[air] = 3100 N - 200 N - 1950 N

F[air] = 950 N

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