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2 years ago

Whose data did Kepler use to describe the motion of the planets?

Physics

2 answers:

lesya [120]2 years ago

8 0

Answer:

A. Tycho Brahe

Explanation:

the person above is correct :)

Levart [38]2 years ago

7 0

Answer:

Tycho Brahe

Explanation:

Tycho Brahe's accurate observations of planetary positions provided the data used by Johannes Kepler to derive his three fundamental laws of planetary motion.

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One form of energy can be _____ another type of energy.

kotegsom [21]

We can answer this one very quickly. From the Law of Conservation of Energy, we know that "Energy can't be created or destroyed.".

So that only leaves us one way to complete the sentence in this question:

"One form of energy can be transformed into another type of energy. " (B)

4 0

3 years ago

When light of wavelength 240 nm falls on a cobalt surface, electrons having a maximum kinetic energy of 0.17 eV are emitted. Fin

dusya [7]

Answer:

(a) 5.04 eV (B) 248.14 nm (c) $1.21\times 10^{15}Hz$

Explanation:

We have given Wavelength of the light \lambda = 240 nm

According to plank's rule ,energy of light

$E = h\nu = \frac{hc}{}\lambda$

$E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV$

Maximum KE of emitted electron i= 0.17 eV

Part( A) Using Einstien's equation

$E = KE_{max}+\Phi _{0}$ , here $\Phi _0$ is work function.

$\Phi _{0}=E - KE_{max}$ = 5.21 eV-0.17 eV = 5.04 eV

Part( B) We have to find cutoff wavelength

$\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}$

$\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }$

$\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm$

Part (C) In this part we have to find the cutoff frequency

$\nu = \frac{c}{\lambda_{cuttoff}}= \frac{3\times 10^{8}m/s}{248.14 \times 10^{-19} m }= 1.21\times 10^{15} Hz$

5 0

3 years ago

A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force act

MA_775_DIABLO [31]

Answer:

cos 0 = 1.

Fs = 7×8 = 56 J

Explanation:

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3 years ago

Las 3 leyes de klepler del sistema planetario AYUDAA¡¡

shtirl [24]

I actually don't know. i speak english.

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3 years ago

What is the SI unit of acceleration and work?

Lerok [7]

A=m/s^2(meter per second square)
Work=joule

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3 years ago