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Vilka [71]
3 years ago
9

Whose data did Kepler use to describe the motion of the planets?

Physics
2 answers:
lesya [120]3 years ago
8 0

Answer:

A. Tycho Brahe

Explanation:

the person above is correct :)

Levart [38]3 years ago
7 0

Answer:

Tycho Brahe

Explanation:

Tycho Brahe's accurate observations of planetary positions provided the data used by Johannes Kepler to derive his three fundamental laws of planetary motion.

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Examples of applied force
Vladimir [108]

Answer:

Push - The most common form of force is a push through physical contact (like a lawnmower or shopping cart)

Pull - You can apply a force by directly pulling on an object (like pulling a wagon)

Explanation:

4 0
3 years ago
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Record your model values in the table below
AlladinOne [14]
There not enough inform here to answer this question
8 0
4 years ago
A stone with a mass m is dropped from an airplane that has a horizontal velocity v at a height h above a lake. If air resistance
seropon [69]

Answer: Option B. R = (1/2)gt^2

Explanation:

S = R (horizontal distance)

V^2 = 2gS

V^2 = 2gR

R = V^2 / 2g

But V = gt

R = (gt)^2 / 2g

R = (g^2 x t^2) / 2g

R = gt^2 / 2

But t^2 = 2h/g

R = ( g x 2h/g) / 2

R = h

But h = (1/2)gt^2

R = h = (1/2)gt^2

4 0
3 years ago
BRAINLEST FOR CORRECT ANSWER
xxMikexx [17]

Answer:

3kg sledgehammer swung at 1.5 m/s

Explanation:

Small Sledgehammer:

Mass:3.0

Velocity:1.5

MASS×VELOCITY=MOMENTUM

3.0×1.5= 4.5 (momentum)

Large Sledgehammer:

Mass:4.0

Velocity:0.9

4.0×0.9=3.6 (momentum)

higher momentum is the smaller Sledgehammer.

3 0
3 years ago
A proton has been accelerated from rest through a potential difference of -1000 v . part a what is the proton's kinetic energy,
wlad13 [49]
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
\Delta U + \Delta K=0
which means
\Delta K = - \Delta U
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (\Delta V=-1000 V):
\Delta U = q \Delta V=(1 eV)(-1000 V)=-1000 eV
Therefore, the kinetic energy gained by the proton is
\Delta K = -(-1000 eV)=1000 eV
<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
4 0
3 years ago
Read 2 more answers
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