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ELEN [110]
3 years ago
13

The resistance is 5 Ω and the amount of electric current is 2 A. This means that the amount of voltage is

Physics
1 answer:
Hatshy [7]3 years ago
3 0

Answer:

I=2A

R=5

Explanation:

formula

V=IR

=2x5

Voltage=10 volt

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

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The mass of a baseball is 100 grams and the volume is 25 cm cubed. What is the density?
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You are kicking your soccer ball back and forth on a soccer field. You kick the ball forward for 10 m. You turn completely aroun
Evgesh-ka [11]

Answer:

1.) Total distance = 70 m

2.) Total displacement = +30m

Explanation:

Distance is a scaler quantity. That is, we will be concerned about its magnitude only and not direction.

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7 0
3 years ago
The mercalli scale is a scale from ________.
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6 0
3 years ago
A positively charged particle of mass 7.2 x 10-8 kg is traveling due east with a speed of 88 m/s and enters a 0.6-T uniform magn
Marianna [84]

Answer:

q = 8.57 10⁻⁵ mC

Explanation:

For this exercise let's use Newton's second law

         F = ma

where force is magnetic force

        F = q v x B

the bold are vectors, if we write the module of this expression we have

         F = qv B sin θ

as the particle moves perpendicular to the field, the angle is θ= 90º

        F = q vB

the acceleration of the particle is centripetal

        a = v² / r

we substitute

        qvB = m v² / r

         qBr = m v

          q =\frac{m\  v}{B\  r}

The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use

          v = d / t

the distance is ¼ of the circle,

          d = \frac{1}{4} \  2\pi  r

           d =\frac{\pi }{2r}

we substitute

           v =  \frac{\pi  r}{2t}

           r = \frac{2 \ t  \ v}{\pi }

           

let's calculate

           r =\frac{2 \ 2.2  \ 10^{-3} \ 88}{\pi } 2 2.2 10-3 88 /πpi

           r = 123.25 m

         

let's substitute the values

           q = \frac{ 7.2 \ 10^{-8} \ 88}{ 0.6 \ 123.25}7.2 10-8 88 / 0.6 123.25

            q = 8.57 10⁻⁸ C

Let's reduce to mC

           q = 8.57 10⁻⁸ C (10³ mC / 1C)

           q = 8.57 10⁻⁵ mC

4 0
3 years ago
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