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ELEN [110]
3 years ago
13

The resistance is 5 Ω and the amount of electric current is 2 A. This means that the amount of voltage is

Physics
1 answer:
Hatshy [7]3 years ago
3 0

Answer:

I=2A

R=5

Explanation:

formula

V=IR

=2x5

Voltage=10 volt

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

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........................ is The force affecting on an object during certain period of time *
Marta_Voda [28]

Answer:

I think c is the answer but I have a little concern on d too

4 0
3 years ago
In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 50
dem82 [27]

Answer:

0.1 m

Explanation:

d = slit width = 0.1 mm = 0.1 x 10⁻³ m

\lambda = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

D = Distance of the screen = 10 m

w = Spacing between successive minima

Spacing between successive minima is given as

w = \frac{2D\lambda }{d}

Inserting the values given

w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}

w = 0.1 m

4 0
3 years ago
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that ha
jasenka [17]

Explanation:

It is given that,

Mass of an object, m=4\times 10^5\ kg

(a) Time period of oscillation, T = 2.4 s

The formula for the time period of spring is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

Where

k is the force constant

k=\dfrac{4\pi ^2 m}{T^2}

k=\dfrac{4\pi ^2 \times 4\times 10^5}{(2.4)^2}

k=2.74\times 10^6\ N/m

(b) Displacement in the spring, x = 2.2 m

Energy stored in the spring is given by :

U=\dfrac{1}{2}kx^2

U=\dfrac{1}{2}\times 2.74\times 10^6\ N/m\times (2.2\ m)^2

U=6.63\times 10^6\ J

Hence, this is the required solution.

7 0
4 years ago
A spring is pulled to 10cm and held in place with a force of 500N. What is the spring constant of the spring
MrMuchimi

Answer:

5000

Explanation:

F=ke where f is the force, k is the spring constant, e is the extension....all in standard units

4 0
3 years ago
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Before a ball rolls down a hill, it has gravitational potential energy. Before a rubber ball bounces away from a surface, it has
rjkz [21]

Answer:

human potential energy

Explanation:

It is given that, before a ball rolls down a hill, it has gravitational potential energy.

Before a rubber ball bounces away from a surface, it has elastic potential energy.  

Human potential energy allows us to throw a ball. While throwing a ball, we have to apply some force by our muscles in order to done some work.Also, we know that the capacity to do work is called energy.

Hence, the correct option is (D) " human potential energy ".

5 0
3 years ago
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