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Contact [7]
3 years ago
15

A person desires to reach a point that is 2.17 km from her present location and in a direction that is 29.6° north of east. Howe

ver, she must travel along streets that are oriented either north-south or east-west. What is the minimum distance she could travel to reach her destination?
Physics
1 answer:
mestny [16]3 years ago
7 0

She needs to move x km in the east-west direction and y km in the north-south direction so that

\sqrt{x^2+y^2}=2.17

and

\tan29.6^\circ=\dfrac yx

Solve the system to get

x=1.89\,\mathrm{km}

y=1.07\,\mathrm{km}

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Singly charged uranium-238 ions are accelerated through a potential difference of 2.90 kV and enter a uniform magnetic field of
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Answer: 0.091 m

Explanation:

r = 1/B * √(2mV/e), where

r = radius of their circular path

B = magnitude of magnetic field = 1.29 T

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V = potential difference = 2.9 kV

e = charge of the Uranium -238 ion = 1.6*10^-19 C

r = 1/1.29 * √[(2 * 238 * 1.6*10^-27 * 2900) / 1.6*10^-19]

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3 years ago
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