Answer:
 a_total = 2 √ (α² + w⁴)
,   a_total = 2,236 m
Explanation:
The total acceleration of a body, if we use the Pythagorean theorem is
           a_total² = a_T²2 +  ²
²
where
the centripetal acceleration is
   a_{c} = v² / r = w r²
tangential acceleration
    a_T = dv / dt
angular and linear acceleration are related
          a_T = α  r
we substitute in the first equation
        a_total = √ [(α r)² + (w r² )²]
        a_total = 2 √ (α² + w⁴)
Let's find the angular velocity for t = 2 s if we start from rest wo = 0
         w = w₀ + α t
         w = 0 + 1.0 2
         w = 2.0rad / s
        
we substitute
         a_total = r √(1² + 2²) = r √5
         a_total = r 2,236
In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m
          a_total = 2,236 m