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Galina-37 [17]
3 years ago
6

What is the magnitude of the total acceleration of point A after 2 seconds? The bar starts from rest and has a constant angular

acceleration of 1.0 rad/s2 clockwise.
Physics
1 answer:
monitta3 years ago
7 0

Answer:

a_total = 2 √ (α² + w⁴) ,   a_total = 2,236 m

Explanation:

The total acceleration of a body, if we use the Pythagorean theorem is

          a_total² = a_T²2 + a_{c}²

where

the centripetal acceleration is

  a_{c} = v² / r = w r²

tangential acceleration

   a_T = dv / dt

angular and linear acceleration are related

         a_T = α  r

we substitute in the first equation

       a_total = √ [(α r)² + (w r² )²]

       a_total = 2 √ (α² + w⁴)

Let's find the angular velocity for t = 2 s if we start from rest wo = 0

        w = w₀ + α t

        w = 0 + 1.0 2

        w = 2.0rad / s

       

we substitute

        a_total = r √(1² + 2²) = r √5

        a_total = r 2,236

In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m

         a_total = 2,236 m

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Answer:

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Explanation:

Given that,

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3 0
3 years ago
Two rollerbladers face each other and stand at rest on a flat parking lot. Tracey has a mass of 32 kg, and Jonas has a mass of 4
satela [25.4K]

Mass of Tracey M1 = 32 kg

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Initially both were at rest

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so answer in two significant figure would be

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