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Aliun [14]
3 years ago
6

The velocity of Desmond’s car changes from 20 meters/second to 10 meters/second. The change happens in 5 seconds. What’s the acc

eleration of the car? Use .
Physics
2 answers:
Sphinxa [80]3 years ago
8 0
V-V₀=at
a=(V-V₀)/t
a=(10-20)/5=-2 m/s²
Acceleration of the car is -2 m/s²
Vikentia [17]3 years ago
4 0
I would say its -2 m/s<span>2 ....hope this help..</span>
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A 30.0-kg girl in a swing is pushed to one side and held at rest by a horizontal force \vec{F} ​F ​⃗ ​​ so that the swing ropes
Virty [35]

Answer:

169.74 N

Explanation:

Given,

Mass of the girl = 30 Kg

angle of the rope with vertical, θ = 30°

equating the vertical component of the tension

vertical component of the tension is equal to the weight of the girl.

 T cos θ = m g

 T cos 30° = 30 x 9.8

 T = 339.48 N

Tension on the two ropes is equal to 339.48 N

Tension in each of the rope = T/2

                                           = 339.48/2 = 169.74 N

Hence, the tension in each of the rope is equal to 169.74 N

7 0
3 years ago
What is the net force experienced by the rope? Include both the magnitude and direction
Lapatulllka [165]

Answer:

All the physical world objects that comers in the contact to exert the force to each other. The contact forces are different from their names and what type of force they exert.

Explanation:

The cables and the ropes are the useful objects that exert the forces that can efficiently transfer the force from a significant distance.

It is noted that tension is a type of force that the rope can not simply push it away effectively. When push happened with rope, the rope goes to slack and lose all the tension that pulls at the first place. Tension only pull objects.

3 0
3 years ago
Electrons are accelerated in the picture tube of a television through potential difference of 8.00 * 10 ^ 3 V. (Use the values q
maria [59]

Answer:

\lambda=1.37\times 10^{-11}\ m

Explanation:

Give that,

The potential difference of the electrons, V=8\times 10^{3}\ V

We need to find the wavelength of the electrons.

Using the conservation of energy,

2meV=\dfrac{h^2}{\lambda^2}\\\\\lambda=\sqrt{\dfrac{h^2}{2meV}}

Put all the values,

\lambda=\sqrt{\dfrac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 8\times 10^3}}\\\\\lambda=1.37\times 10^{-11}\ m

So, the wavelength of the electrons is 1.37\times 10^{-11}\ m.

7 0
2 years ago
Place the following into scientific notation...(.000635)<br> *
AleksAgata [21]
6.35x10^-4 OR 6.3x10-4 (if only one decimal number is allowed)
6 0
3 years ago
Why might a scientist repeat an experiment if she did not make a mistake in the first one?
iren2701 [21]

Answer:

B

Explanation:

4 0
3 years ago
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