Na + NaNO3 = Na2O + N2
4 Na + 2 NaNO3 = 6 Na2O + N2
6 Na on each side
2 N on each side
6 O on each side
The large piece of jewelry that has a mass of 132.6 g and when is submerged in a graduated cylinder that initially contains 48.6 ml water and the volume increases to 61.2 ml once the piece of jewelry is submerged, has a density of: 10.523 g/ml
To solve this problem the formulas and the procedures that we have to use are:
Where:
- d= density
- m= mass
- v= volume
- v(f) = final volume
- v(i) = initial volume
Information about the problem:
- m = 132.6 g
- v(i) = 48.6 ml
- v(f) = 61.2 ml
- v = ?
- d =?
Applying the volume formula we get:
v = v(f)-v(i)
v = 61.2 ml - 48.6 ml
v = 12.6 ml
Applying the density formula we get:
d = m/v
d = 132.6 g/12.6 ml
d = 10.523 g/ml
<h3>What is density?</h3>
It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
Learn more about density in: brainly.com/question/1354972
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Answer:
kL, dL, mL, pL
Explanation:
pL stands for picoliters. This is equal to 1 × 10⁻¹² (0.000000000001) liters.
mL stands for milliliters. This is equal to 1 × 10⁻³ (0.001) liters.
dL stands for deciliters. This is equal to 1 × 10⁻¹ (0.1) liters.
kL stands for kiloliters. This is equal to 1 × 10³ (1000) liters.
<span>Kwang Jeon observed that Amoeba had been attacked by a bacterial infection, and lots of the Amoeba had
died. However, some survived and continued to reproduce. After investigating the remaining
Amoeba and their offspring, he noticed they were very healthy. He thought maybe they were able to
fight off the bacteria, but instead, he found they were still infected with the bacteria but were not
dying. The bacteria were no longer making the Amoeba sick. Then, he killed off the bacteria using
antibiotics and was surprised to see that the Amoeba also died. It seemed the Amoeba and bacteria
had formed a relationship in which they both needed each other to survive. After researching, Jeon
found that the bacteria made a protein that the Amoeba needed to survive. </span>
Answer:
-65.897°C.
Explanation:
- Adding solute to water causes depression of the boiling point.
- The depression in freezing point (ΔTf) can be calculated using the relation: <em>ΔTf = Kf.m,</em>
where, ΔTf is the depression in freezing point of chloroform solution.
Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).
m is the molality of the solution (m = 0.51 m).
∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.
∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.
