1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alik [6]
3 years ago
8

How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​

Physics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

 Mathematically;

        Power  = \frac{work done}{time}  

   Time  = \frac{work done}{power}  

 Work done  = weight x height

 convert mass to kg;

     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

          1000mm = 1m

          6.34 x 10⁴mm gives 63.4m

  Work done  = 14.7 x 9.8 x 63.4 = 9133.4J

  Time taken = \frac{9133.4}{2190}   = 4.2s

You might be interested in
Considering the factors that affect gravitational pull, in which location would the gravitational pull from the earth be SMALLES
OleMash [197]
C. The higher the altitude the less gravity affects you
4 0
3 years ago
A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo
zloy xaker [14]

Solution :

Given :

Mass attached to the spring = 4 kg

Mass dropped = 6 kg

Force constant = 100 N/m

Initial amplitude = 2 m

Therefore,

a). $v_{initial} = A w$

          $= 2 \times \sqrt{\frac{100}{4}}$

          = 10 m/s

Final velocity, v at equilibrium position, v = 5 m/s

Now, $\frac{1}{2}(4+4)5^2 = \frac{1}{2} kA'$

A' = amplitude = 1.4142 m

b). $T=2 \pi \sqrt{\frac{m}{k}}$

    m' = 2m

    Hence, $T'=\sqrt2 T$

c). $\frac{\frac{1}{2}(4+4)5^2 + \frac{1}{2}\times 4 \times 10^2}{\frac{1}{2} \times 4 \times 10^2}$

  $=\frac{1}{2}$

Therefore, factor $=\frac{1}{2}$

Thus, the energy will change half times as the result of the collision.

7 0
3 years ago
What’s the four missing blanks in this diagram?
sergey [27]

Answer:

                                                    Matter

                Pure substances                                        Mixture

Element                         compound         Homogenous           Heterogenous

7 0
3 years ago
Four springs with the following spring constants, 113.0 N/m, 65.0 N/m, 102.0 N/m, and 101.0 N/m are connected in series. What is
Llana [10]

Answer:

K_e_q=22.75878093\frac{N}{m}

f=1.363684118Hz

Explanation:

In order to calculate the equivalent spring constant we need to use the next formula:

\frac{1}{K_e_q} =\frac{1}{K_1} +\frac{1}{K_2} +\frac{1}{K_3} +\frac{1}{K_4}

Replacing the data provided:

\frac{1}{K_e_q} =\frac{1}{113} +\frac{1}{65} +\frac{1}{102} +\frac{1}{101}

K_e_q=22.75878093\frac{N}{m}

Finally, to calculate the frequency of oscillation we use this:

f=\frac{1}{2(pi)} \sqrt{\frac{k}{m} }

Replacing m and k:

f=\frac{1}{2(pi)} \sqrt{\frac{22.75878093}{0.31} } =1.363684118Hz

4 0
3 years ago
Planet a and planet b are in circular orbits around a distant star. planet a is 7.8 times farther from the star than is planet
gogolik [260]
To find the ratio of planetary speeds Va/Vb we need the orbital velocity formula: 

V=√({G*M}/R), where G is the gravitational constant, M is the mass of the distant star and R is the distance of the planet from the star it is orbiting. 

So Va/Vb=[√( {G*M}/Ra) ] / [√( {G*M}/Rb) ], in our case Ra = 7.8*Rb 

Va/Vb=[ √( {G*M}/{7.8*Rb} ) ]  / [√( {G*M}/Rb )], we put everything under one square root by the rule: (√a) / (√b) = √(a/b) 

Va/Vb=√ [ { (G*M)/(7.8*Rb) } / { (G*M)/(Rb) } ], when we cancel out G, M and Rb we get:

Va/Vb=√(1/7.8)/(1/1)=√(1/7.8)=0.358 so the ratio of Va/Vb = 0.358.  
6 0
3 years ago
Other questions:
  • Which of the following is a chemical equation that accurately represents what happens when sulfur and oxygen react to form sulfu
    7·1 answer
  • Which action might lead scientists to develop new explanations about the
    13·2 answers
  • A 100-kg tackler moving at a speed of 2.6 m/s meets head-on (and holds on to) an 92-kg halfback moving at a speed of 5.0 m/s. Pa
    11·1 answer
  • Why is most space exploration accomplished with spacecraft that do not have astronauts on board
    6·2 answers
  • WILL GIVE 5 STARS!!!! HELP ASAP!!!
    14·1 answer
  • Which feature of a soundwave is related to pitch
    13·2 answers
  • A 97.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.63 r
    6·1 answer
  • PLEASE HELP! I'LL GIVE BRAINLEST​
    10·1 answer
  • A custodian pushes a 119 kg box across a level floor. The box moves at a constant velocity. The custodian pushes horizontally on
    12·1 answer
  • A rocket takes off from Earth's surface, accelerating straight up at 31.2 m/s2. Calculate the normal force (in N) acting on an a
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!