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Alik [6]
3 years ago
8

How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​

Physics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

 Mathematically;

        Power  = \frac{work done}{time}  

   Time  = \frac{work done}{power}  

 Work done  = weight x height

 convert mass to kg;

     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

          1000mm = 1m

          6.34 x 10⁴mm gives 63.4m

  Work done  = 14.7 x 9.8 x 63.4 = 9133.4J

  Time taken = \frac{9133.4}{2190}   = 4.2s

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3 years ago
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cricket20 [7]

Answer;

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Why does the sky change colors at sunset?
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A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and
victus00 [196]

Answer:

a)  t=195.948N.m

b)  \phi=13.6 \textdegree

Explanation:

From the question we are told that:

Density \rho=1.225kg/m^2

Velocity of wind v=14m/s

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient \mu=2.05

a)

Generally the equation for Force is mathematically given by

F=\frac{1}{2}\muA\rhov^2

F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2

F=163.29

Therefore Torque

t=F*r*sin\theta

t=163.29*1.2*sin90

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b)

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d=sin \phi

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5 0
3 years ago
If a bullet travels at 593.0 m/s, what is its speed in miles per hour?
Ksenya-84 [330]

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Thus we can convert the units of the given quantity.

That is,

593\;m/s=593\;\frac{1/1609.34}{1/3600} \;miles/hour\\
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The quantity is converted to the required units.


7 0
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