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3 years ago

Electromagnetic waves differ from the other types of waves because they are

Physics

2 answers:

suter [353]3 years ago

6 0

Answer:

Electromagnetic waves differ from the other types of waves because they are energy waves which do not require material medium for their propagation, and as such they travel through vacuum.

Explanation:

A wave can be either mechanical or electromagnetic.

Electromagnetic waves are those types of waves which do not require material medium for their propagation. While mechanical waves are those types of waves which require material medium for their propagation.

Electromagnetic waves differ from the other types of waves because they are energy waves which do not require material medium for their propagation, and as such they travel through vacuum.

Ronch [10]3 years ago

4 0

Correct answer choice is :

B) Able to travel through a vacuum.

Explanation:

Electromagnetic waves are applied to carry long/short/FM wavelength radio waves, and TV/telephone/wireless signals or services. They are also effective for transferring energy in the form of microwaves, infrared radiation, visible light, ultraviolet light, X-rays, and gamma rays. Electromagnetic waves change from mechanical waves in that they do not need a medium to generate. This means that electromagnetic waves can move not only in the air and solid matters but also in the void of space.

Read more on Brainly.com - brainly.com/question/1697984#readmore

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Two long, parallel wires are separated by 2.2 mm. Each wire has a 32-AA current, but the currents are in opposite directions. Pa

Alex

Answer:

$B=1.1636*10^{-3}T$

Explanation:

Given data

$d_{wires}=2.2mm=0.022m\\ I_{current}=32A\\$

To find

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Solution

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3 years ago

A circular radar antenna on a Coast Guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 GHz. Two small boats

Anna35 [415]

Answer:

d = 76.5 m

Explanation:

To find the distance at which the boats will be detected as two objects, we need to use the following equation:

$\theta = \frac{1.22 \lambda}{D} = \frac{d}{L}$

Where:

θ: is the angle of resolution of a circular aperture

λ: is the wavelength

D: is the diameter of the antenna = 2.10 m

d: is the separation of the two boats = ?

L: is the distance of the two boats from the ship = 7.00 km = 7000 m

To find λ we can use the following equation:

$\lambda = \frac{c}{f}$

Where:

c: is the speed of light = 3.00x10⁸ m/s

f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz

$\lambda = \frac{c}{f} = \frac{3.00 \cdot 10^{8} m/s}{16.0 \cdot 10^{9} s^{-1}} = 0.0188 m$

Hence, the distance is:

$d = \frac{1.22 \lambda L}{D} = \frac{1.22*0.0188 m*7000 m}{2.10 m} = 76.5 m$

Therefore, the boats could be at 76.5 m close together to be detected as two objects.

I hope it helps you!

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3 years ago

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PIT_PIT [208]

Hello,

The answer is "0.00349 hL".

Reason:

34.9cL=0.00349hL

(Remember to go left 6 places when doing this question)

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

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aleksandr82 [10.1K]

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