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3 years ago

Electromagnetic waves differ from the other types of waves because they are

Physics

2 answers:

suter [353]3 years ago

6 0

Answer:

Electromagnetic waves differ from the other types of waves because they are energy waves which do not require material medium for their propagation, and as such they travel through vacuum.

Explanation:

A wave can be either mechanical or electromagnetic.

Electromagnetic waves are those types of waves which do not require material medium for their propagation. While mechanical waves are those types of waves which require material medium for their propagation.

Electromagnetic waves differ from the other types of waves because they are energy waves which do not require material medium for their propagation, and as such they travel through vacuum.

Ronch [10]3 years ago

4 0

Correct answer choice is :

B) Able to travel through a vacuum.

Explanation:

Electromagnetic waves are applied to carry long/short/FM wavelength radio waves, and TV/telephone/wireless signals or services. They are also effective for transferring energy in the form of microwaves, infrared radiation, visible light, ultraviolet light, X-rays, and gamma rays. Electromagnetic waves change from mechanical waves in that they do not need a medium to generate. This means that electromagnetic waves can move not only in the air and solid matters but also in the void of space.

Read more on Brainly.com - brainly.com/question/1697984#readmore

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Consider the hydrogen atom. How does the energy difference between adjacent orbit radii change as the principal quantum number i

Kisachek [45]

Answer:

the energy difference between adjacent levels decreases as the quantum number increases

Explanation:

The energy levels of the hydrogen atom are given by the following formula:

$E=-E_0 \frac{1}{n^2}$

where

$E_0 = 13.6 eV$ is a constant

n is the level number

We can write therefore the energy difference between adjacent levels as

$\Delta E=-13.6 eV (\frac{1}{n^2}-\frac{1}{(n+1)^2})$

We see that this difference decreases as the level number (n) increases. For example, the difference between the levels n=1 and n=2 is

$\Delta E=-13.6 eV(\frac{1}{1^2}-\frac{1}{2^2})=-13.6 eV(1-\frac{1}{4})=-13.6 eV(\frac{3}{4})=-10.2 eV$

While the difference between the levels n=2 and n=3 is

$\Delta E=-13.6 eV(\frac{1}{2^2}-\frac{1}{3^2})=-13.6 eV(\frac{1}{4}-\frac{1}{9})=-13.6 eV(\frac{5}{36})=-1.9 eV$

And so on.

So, the energy difference between adjacent levels decreases as the quantum number increases.

5 0

3 years ago

What is the KE if a 10kg mass traveling at 5 m/s

11111nata11111 [884]

Answer: KE = 25 J

Explanation: You must use the formula

KE = 1/2 m v²

to solve this problem.

KE = 1/2 (10 Kg) (5 m/s)

KE = 1/2 (50 kgm/s)

KE = 25 J

7 0

2 years ago

What is sludge dumping?<br>HELP ASAP PLEASE

yulyashka [42]

Answer:

What is sludge dumping? Sludge is the solid waste in raw sewage. Sludge dumping is discharging that waste into the ocean.

Explanation:

5 0

3 years ago

Which temperature scale has the highest value for the boiling point of water?

drek231 [11]

Answer: The correct answer is kelvin.

Explanation:

The expression for the conversion of degree Celsius to Kelvin is as follows:

K= 273 + degree Celsius

The expression for the conversion of degree Celsius to Fahrenheit is as follows:

$F=(Degree Celsius\times \frac{9}{5})+ 32$

The freezing point of water on Celsius degree is zero degree Celsius. The freezing point on kelvin scale is 273.15 K.

The boiling point of water on Celsius degree is 100 degree Celsius. The boiling point on kelvin scale is 373.15 K. The boiling point on Fahrenheit scale is 373.15 K.

Therefore, Kelvin scale has the highest value for the boiling point of water.

6 0

3 years ago

A 20.00 kg lead sphere is hanging from a hook by a thin, massless wire 2.80 m long and is free to swing in a complete circle. Tr

Tema [17]

The minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 58.5 m/s.

<h3>Minimum speed for the object not fall out of the circle</h3>

The minimum speed if given by tension in the wire;

T + mg = ma

T + mg = m(v²)/R

tension must be zero for the object not fall

0 + mg = mv²/R

v = √(Rg)

<h3>Final speed of the two mass after collision</h3>

Use the principle of conservation of energy

K.Ef = K.Ei + P.E

¹/₂mvf² = ¹/₂mv² + mg(2R)

¹/₂vf² = ¹/₂v² + g(2R)

¹/₂vf² = ¹/₂(Rg) + g(2R)

vf² = Rg + 4Rg

vf² = 5Rg

vf = √(5Rg)

vf = √(5 x 2.8 x 9.8)

vf = 11.7 m/s

<h3>Initial speed of the dart</h3>

Apply principle of conservation of linear momentum for inelastic collision;

5v = vf(20 + 5)

5v = 11.7(25)

5v = 292.5

v = 58.5 m/s

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

3 0

1 year ago