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irinina [24]
3 years ago
12

Los rieles de una vía de tren de acero tienen 1500 m de longitud. ¿Qué longitud tendrá cuando

Physics
1 answer:
melomori [17]3 years ago
6 0

Answer:

can you translate the question

into english

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Every magnet must have what at its ends?
slega [8]

Explanation:

The correct is A.

every magnet have two pole

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2 years ago
A cart of mass M = 2.40 kg can roll without friction on a level track. A light string draped over a light, frictionless pulley c
sergiy2304 [10]

Answer:

Part a)

a_{hanger} = g - \frac{T}{m}

Part b)

a_{cart} = \frac{T}{M}

Part c)

a = \frac{mg}{M + m}

Part d)

a = 1.35 m/s^2

Explanation:

Part a)

For hanger we know that it will have tension force upwards while it has downwards its weight so we will have

mg - T = ma

so we have

a_{hanger} = g - \frac{T}{m}

Part b)

now for car that is rolling on the floor the net force is given as

F = Ma

T = Ma

a_{cart} = \frac{T}{M}

Part c)

now we know that the cart and the hanger both are connected to each other

so they must have same acceleration

so we will have

T = Ma

mg - Ma = ma

a = \frac{mg}{M + m}

Part d)

now we know that

M = 2.40 kg

m = 0.50 kg

so we will have

a = \frac{0.50(9.81)}{2.40 + 0.50}

a = 1.35 m/s^2

6 0
3 years ago
A/an ___ is a machine which tells us about the strength and speed of sisemec waves.
svp [43]
The answer is Seismograph
3 0
3 years ago
Read 2 more answers
A compound machine is sued to lift a car. If you apply a force of 60 N to the machine, it lifts the car with a force of 550 N.
mrs_skeptik [129]

a) MA=550/60=9.17

b) Wu=1150*0.35=402.5 J

3 0
3 years ago
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When an electron falls from a higher to a lower energy level in an atom, the photon released has a wavelength of 121.6 nm. What
yarga [219]

Answer:

\Delta E=1.64*10^{-18}J

Explanation:

The energy difference between the energy levels involved in the transition of the electron is directly proportional to the frequency of the emitted photon:

\Delta E=h\nu(1)

Where h is the Planck constant. The photon's frequency is inversely proportional to its wavelegth:

\nu=\frac{c}{\lambda}(2)

Here c is the speed of light. Replacing (2) in (1):

\Delta E=\frac{hc}{\lambda}\\\Delta E=\frac{(6.63*10^{-34}J\cdot s)(3*10^8\frac{m}{s})}{121.6*10^{-9}m}\\\Delta E=1.64*10^{-18}J

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3 years ago
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