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irinina [24]
2 years ago
12

Los rieles de una vía de tren de acero tienen 1500 m de longitud. ¿Qué longitud tendrá cuando

Physics
1 answer:
melomori [17]2 years ago
6 0

Answer:

can you translate the question

into english

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Help please help!! Pleaseee
sladkih [1.3K]

Answer:

The coastal regions are affected by abrasion due to large volumes of water and increased winds. This can become more severe especially with storms that hit coastal regions.

Explanation:

Abrasion is physical weathering caused by water, wind and gravity.  Hope it worked, I love geography! Can you mark mine as the brainliest please! Also can you give me a thanks and a 5 star vote!

5 0
3 years ago
Sound cannot travel through___________.
lana [24]

d.) a and b only

This is because sound needs a medium to travel.  It can travel in a solid (the fastest) and air for example.  Sound waves cannot propagate through a vacuum and since space is a vacuum the answer is a and b only.

5 0
2 years ago
A force pointing in the xx-direction is given by F=ax3/2F=ax3/2, where aa is a constant. The force does 2.01 kJkJ of work on an
damaskus [11]

Answer:

Explanation:

Given that

F=ax^3/2. a is a constant

The force does a work of

W=2.01KJ from x=0 to x=15.2m

We need to find a

Work is give as,

W=∫F.ds

But this is in x direction only then,

W=∫Fdx. from x=0 to x=15.2m

W=∫ax^3/2dx from x=0 to x=15.2m

W=ax^(3/2+1)/(3/2+1).

W=ax^(5/2)/5/2

W=ax^(2/5)/2.5 from x=0 to x=15.2m

Cross multiply

2.5W=ax^2.5. from x=0 to x=15.2m

2.5W= a (15.2^2.5-0)

W=2.01KJ=2010J

2.5×2010=a×900.76

Therefore,

a=5.56

7 0
2 years ago
A large room in a house holds 947 kg of dry air at 33.2°C. A woman opens a window briefly and a cool breeze brings in an additio
BartSMP [9]

Answer:

31.96362 °C

Explanation:

m_1 = Mass of air in the room = 947 kg

m_2 = Mass of air entering the room = 62.4 kg

T_1 = Temperature in the room = 33.2°C

T_2 = Temperature air entering the room = 13.2°C

T = Equilibrium temperature

c = Specific heat of air = 1006 J/kg °C

In the case of thermal equilibrium we have the relation

m_1c(T_1-T)=m_2c(T-T_2)\\\Rightarrow T=\frac{m_2T_2+m_1T_1}{m_1+m_2}\\\Rightarrow T=\frac{62.4(13.2+273.15)+947(33.2+273.15)}{947+62.4}\\\Rightarrow T=305.11362\ K=305.11362-273.15=31.96362^{\circ}C

The temperature of thermal equilibrium is 31.96362 °C

7 0
3 years ago
If the temperature is held constant during this process and the final pressure is 671 torr , what is the volume of the bulb that
MariettaO [177]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

Explanation:

From the question we are told that

   The initial pressure of the gas is  P_1 =  1.50 \  atm

   The volume of the second bulb is  V_2 =  0.800 \  L

   The  final pressure of the gas is  P_2 =  671 \ torr =  \frac{671 }{ 760}  =  0.883 \ atm

Let the unknown volume be represented as V_1 =  V \   L

Generally from Boyle's law we have that

      P_1 *  V_1 =  P_2 * V_2

=>   1.50 *  V =   0.883  * 0.800

=>   V  = 0.479 \ L

         

4 0
2 years ago
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