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3 years ago

Design your own plan for a scientific experiment. You do not have to conduct your experiment.

Physics

1 answer:

olganol [36]3 years ago

8 0

you could use one of your scientific experiments you did over the past few years.

You could make an solinoid.

Hope this helps! Lol

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Below is a diagram of the orbits of the inner planets examine the diagram and answer questions three and four

drek231 [11]

Answer:

C is the answer

Explanation:

Earth is the third planet from the sun

you are cheating on your test, I know

3 0

3 years ago

Read 2 more answers

As a summer intern assigned to the Olympics Kayaking committee, you need to determine the speed of water flowing through a rapid

Nookie1986 [14]

Answer:

11.56521 m/s

Explanation:

$A_1$ = Area of first section = $14\times 2$

$A_2$ = Area of second section = $5\times 0.92$

$V_1$ = Velocity in first section = 1.9 m/s

$V_2$ = Velocity in second section

From the continuity equation we get

$A_1V_1=A_2V_2\\\Rightarrow V_2=\dfrac{A_1V_1}{A_2}\\\Rightarrow V_2=\dfrac{14\times 2\times 1.9}{5\times 0.92}\\\Rightarrow V_2=11.56521\ m/s$

The speed of the river through the section of rapids is 11.56521 m/s

5 0

3 years ago

The diameters of apples from a certain farm follow the normal distribution with mean 4 inches and standard deviation 0.4 inch. A

trasher [3.6K]

Answer:

The probability for the proportion of apples with diameters less than 3.5 inches is 0.1056.

Explanation:

For a normal distribution, z score is calculated using this formula: (X-μ)/σx

Where Mean, μ = 4

Standard deviation, σ = 0.400

The probability for the proportion of apples with diameters less than 3.5 inches is expressed below:

Probability = P(X<3.5)

= P(Z<-1.25)

Probability = 0.1056

7 0

3 years ago

Read 2 more answers

The radius of the thinner wire is 0.22 mm and the radius of the thick wire is 0.55 mm. There are 4.0 x 1028 mobile electrons per

Natasha_Volkova [10]

Answer:

0.2631 N/C

Explanation:

Given that:

The radius of the wire r = 0.22 mm = 0.22 × 10⁻³ m

The radius of the thick wire r' = 0.55 mm = 0.55 × 10⁻³ m

The numbers of electrons passing through B, N = 6.0 × 10¹⁸ electrons

Electron mobility μ = 6.0 x 10-4 (m/s)/(N/C)

= 0.0006

The number of electron flow per second is calculated as follows:

$I = \frac{q}{t}$

$I = \frac{Ne}{t}$

$I = \frac{6*10^{18}(1.6*10^{-18})C}{1 \ s}$

$I = 0.96 \ A$

The magnitude of the electric field is:

E = $\frac{I}{ \mu n eA}$

E = $\frac{I}{ \mu n e(\pi r^2)}$

E = $\frac{0.96}{(0.0006 m/s N/C ) (4*10^{28})(1.6*10^{-19}C)(0.55*10^{-3}m)^2}$

E = 0.2631 N/C

8 0

3 years ago

"Consider the Earth and the Moon as a two-particle system. (a) How far from the center of the Earth is the gravitational field o

olga55 [171]

a is the correct

Explanation:

hope you like then comment

3 0

3 years ago