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GaryK [48]
3 years ago
7

one type of wave used to transmit a signal is a ultraviolet wave. infrared wave. radio wave. x-ray wave.

Physics
2 answers:
sammy [17]3 years ago
6 0
Please be more specific because they all transmit signals but the most common one is the radio wave because it transmits cellphone , televition and radio signals
Korvikt [17]3 years ago
6 0

Answer:

Radio Waves

Explanation:

Radio waves are of longest wavelength and with smallest frequency

So here we can say that the wavelength range is very large and frequency range is less so here these waves are safe to use as these are not dangerous to us.

Since all electromagnetic waves consist of energy of different range depends on the frequency of the waves so in order to use them for communication purpose we have to use those waves which will have less energy so that these waves will remain useful for us.

So here correct answer for communication purpose will be

RADIO WAVE

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Answer: C

Explanation:

Bro this is common sense. Throw something across the room and watch it. It isnt going to be repulsed and fly up. It also isnt going to continue on forever. It will clearly fall and hit the ground

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Answer:

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Explanation:

use the formula:

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A football punter wants to kick the ball so that it is in the air for 4.5 s and lands 50 m from where it was kicked. Assume that
irakobra [83]

Answer:

(a) The angle of projection is 63 degree.

(b) The velocity of projection is 24.5 m/s.

Explanation:

Height, h = 1 m

horizontal distance, d = 50 m

time, t = 4.5 s

Let the initial velocity is u and the angle is A.

(a) Horizontal distance = horizontal velocity x time

50 = u cos A x 4.5

u cos A = 11.1 .....(1)

Use second equation of motion in vertical direction

h = u t + 0.5 gt^2\\\\- 1 = u sin A \times 4.5 - 0.5 \times 9.8\times 4.5^2\\\\u sin A = 21.8 ..... (2)

Divide (2) by (1)

tan A = 1.97

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(b) Substitute the value of A in equation (2)

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7 0
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A parallel-plate capacitor with circular plates of radius R is being charged by a battery, which provides a constant current. At
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To solve this problem it is necessary to apply the concepts related to the magnetic field.

According to the information, the magnetic field INSIDE the plates is,

B=\frac{1}{2} \mu \epsilon_0 r

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\mu =Permeability constant

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From this deduction we can verify that the distance is proportional to the field

B \propto r

Then the distance relationship would be given by

\frac{r}{R} = \frac{B}{B_{max}}

r =\frac{B}{B_{max}} R

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r = 0.5R

On the outside, however, it is defined by

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Here the magnetic field is inversely proportional to the distance, that is

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r = 2R

7 0
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