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GaryK [48]
3 years ago
7

one type of wave used to transmit a signal is a ultraviolet wave. infrared wave. radio wave. x-ray wave.

Physics
2 answers:
sammy [17]3 years ago
6 0
Please be more specific because they all transmit signals but the most common one is the radio wave because it transmits cellphone , televition and radio signals
Korvikt [17]3 years ago
6 0

Answer:

Radio Waves

Explanation:

Radio waves are of longest wavelength and with smallest frequency

So here we can say that the wavelength range is very large and frequency range is less so here these waves are safe to use as these are not dangerous to us.

Since all electromagnetic waves consist of energy of different range depends on the frequency of the waves so in order to use them for communication purpose we have to use those waves which will have less energy so that these waves will remain useful for us.

So here correct answer for communication purpose will be

RADIO WAVE

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a 1.2x10^3 kilogram car is accelerated uniformly from 10. meters per second to 20 meters per second in 5.0 seconds. what is the
irinina [24]
Force , F = ma

F =  m(v - u)/t               

Where m = mass in kg, v= final velocity in m/s, u = initial velocity in m/s
t = time, Force is in Newton.

m= 1.2*10³ kg,  u = 10 m/s,  v = 20 m/s, t = 5s

F =  1.2*10³(20 - 10)/5

F = 2.4*10³ N = 2400 N


7 0
3 years ago
Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 30.0 mph and half the
salantis [7]

Answer:

Explanation:

Given

Distance to grandmother's house=100 mi

it is given that during return trip Julie spend equal time driving with speed 30 mph and 70 mph

Let Julie travel x mi with 30 mph and 100-x with 70 mph

\frac{x}{30}=\frac{100-x}{70}

x=30 mi

Therefore

Julie's Average speed on the way to Grandmother's house=\frac{100}{\frac{50}{30}+\frac{50}{70}}

=42 mph

On return trip

=\frac{100}{2\frac{30}{30}}=50 mph

6 0
3 years ago
****PLEASE HELP**** THERE ARE TWO QUESTIONS (ITS EASY)
notka56 [123]

but I think it's a and f

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b and e

3 0
3 years ago
Which objects would sink in honey, which has a density of 1.4 g/cm³? Check all that apply.
bazaltina [42]

Answer:

any object that has density more than 1.4

Explanation:

The object that has density more than 1.4 is denser than the honey

6 0
3 years ago
Read 2 more answers
A large airplane typically has three sets of wheels: one at the front and two farther back, one on each side under the wings. Co
Tems11 [23]

(a) The force the ground exerts on each set of rear wheels when the plane is at rest on the runway is 0.743 MN.

(b) The force the ground exerts on the front set of wheels is 0.239 MN.

<h3>Center mass of the airplane</h3>

The concept of center mass of an object can be used to dtermine the mass distribution of the airplane along the line through the center.

<h3>Some assumptions</h3>
  • The wheels under the wind do not pass through the center line.
  • The position of the front wheel is constant and it is zero mark (origin).
  • The rear wheels are at 21.7 m mark

Position of the center mass of the plane is calculated as follows;

Let the position of the center mass, Xcm = y

the center mass is 3 m in front of rear wheels, that is

21.7 - y = 3

y = 21.7 - 3

y = 18.7 m

Xcm = 18.7 m

<h3>Mass of the plane at the position of the rear wheels</h3>

Let the mass of the plane at front wheels = M1

Let the mass of the plane at rear wheels = M2

X_{cm} = \frac{M_1x_1 + M_2x_2}{M_1 + M_2}

18.7 = \frac{M_1(0) + M_2(21.7)}{177000} \\\\3,309,900 = 21.7M_2\\\\M_2 = \frac{3,309,900}{21.7} \\\\M_2 = 152,529.95 \ kg

<h3>Force exerted by the ground on each rear wheel</h3>

There are two rear wheels, and the force exerted on each wheel due to mass of the airplane at this position is calculated as follows;

W = mg\\\\W_1 = W_2 = \frac{1}{2} (mg) = \frac{1}{2} (152,529.95 \times 9.8) = 743,396.76 \ N= 0.743 \ MN

<h3>Mass of the plane at the position of the front wheel</h3>

M1 + M2 = 177,000

M1 = 177,000 - M2

M1 = 177,000 - 152,529.95

M1 = 24,470.05 kg

<h3>Force exerted by the ground on the front wheel</h3>

W = mg

W = 24,470.05 x 9.8

W = 239,806.5 N = 0.239 MN

Learn more about center mass here: brainly.com/question/13499822

7 0
2 years ago
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