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kupik [55]
3 years ago
5

An equipoterntial surface that surrounds a + 3.0 pC point charge has a radius of 2.0 cm. What is the potential of this surface?​

Physics
1 answer:
mestny [16]3 years ago
8 0

Answer:

Electric potential = 0.00054 V

Explanation:

We are given;

Charge; q = 3 pC = 3 × 10^(-12) C

Radius; r = 2 cm = 0.02 m

Formula for the electric potential of this surface will be;

V = kqr

Where;

K is a constant = 9 × 10^(9) N⋅m²/C².

Thus;

V = 9 × 10^(9) × 3 × 10^(-12) × 0.02

V = 0.00054 V

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Answer:

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Explanation:

The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4

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Answer:

<h3>25km/hr</h3>

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3 years ago
The suspension system of a 2100 kg automobile "sags" 8.5 cm when the chassis is placed on it. Also, the oscillation amplitude de
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Answer:

Part a)

k = 6.06 \times 10^4 N/m

Part b)

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Explanation:

Part a)

as the mass of the suspension system is given as

m = 2100 kg

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x = 8.5 cm

so now for force balance we have

mg = kx

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Part b)

Now we know that amplitude decreases by 63% in each cycle

so after one cycle the amplitude will become 37% of initial amplitude

so it is given as

A = 0.37 A_o

also we know

A = A_o e^{-bt/2m}

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t = 2\pi\sqrt{\frac{m}{k}}

t = 2\pi\sqrt{\frac{525}{6.06 \times 10^4}}

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now damping constant is

b = \frac{2(525)}{0.58}

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3 years ago
A stone weighing 0.7 kilograms rolls down the inclined plane from position B to position A. Position A is located at sea level.
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