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Drupady [299]
3 years ago
12

Which term best describes liquid behavior under pressure?

Chemistry
1 answer:
BartSMP [9]3 years ago
3 0
The correct answer is incompressible. Liquids or fluids that behave under pressure are called incompressible fluids because they tend to behave through flowing movements. An example of an incompressible fluid is the lava which comes out of a volcano where once out of the atmosphere becomes dense and flows at a constant volume and velocity.
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Phenol (C6H5OH) is often used as an antiseptic in mouthwashes and throat lozenges. If a mouthwash has a phenol concentration of
amm1812

Answer:

M=0.16M

Explanation:

Hello!

In this case, since the molarity is defined as moles of solute divided by liters of solution, since we have phenol with a molar mass of 94.12 g/mol, we can first compute the moles in 1.5 g of phenol:

n=1.5g*\frac{1mol}{94.12 g}=0.016mol

Next, since 1000 mL = 1 L, we notice that the volume of the solution is 0.100 L and therefore, the molarity of such solution turns out:

M=\frac{n}{V}=\frac{0.016mol}{0.100L}\\\\M=0.16M

Best regards!

3 0
2 years ago
What is the steric number of H2O2?
chubhunter [2.5K]

Answer: 1(2)+6(2)=14

Explanation:

Not sure, but maybe.

8 0
3 years ago
57. A recipe for s'mores calls for 2 graham crackers, 2 chocolate pieces and 1 marshmallow. If I
geniusboy [140]

Answer:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

Explanation:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

5 0
2 years ago
When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e
sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂  

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

                2 Al(s)  +  3Cl₂(g)  ⇒   2AlCl₃

Process

a) Calculate the molar mass of the reactants  

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion  Al/Cl₂ = 53.96/212.7 = 0.254

   Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

                    53.96 g of Al ------------------ 212.7 g of Cl₂

                     40.5 g of Al -------------------  x

                      x = (40.5 x 212.7) / 53.96

                      x = 8614.35 / 53.96

                      x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

                  = 53.057 g

d) Calculate the moles of Cl

                       35.45 g of Cl ----------------- 1 mol

                       53.057 g of Cl ---------------  x

                        x = (53.057 x 1)/35.45

                       x = 1.49 mol of Cl₂                    

6 0
3 years ago
Read 2 more answers
A qué temperatura en grados centígrados se encuentra la Luna, si se sabe que está en 3 Kelvin aproximadamente?
Viktor [21]

Answer:

Can you do it in english please don't understand Spanish much. thanks

4 0
2 years ago
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