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statuscvo [17]
3 years ago
9

the amount of heat involved in the synthesis of 1 mole of a compound from its elements with all substances in their standard sta

tes at 25 degrees celcius is called
Chemistry
2 answers:
otez555 [7]3 years ago
4 0

<span>The </span>standard enthalpy of formation<span> <span>is defined as the change in </span></span>enthalpy<span> <span>when one mole of a substance in the </span></span>standard<span> <span>state (1 atm of pressure and temperature of 298.15 K) is </span></span>formed<span> <span>from its pure elements under the same conditions.</span></span>

vodka [1.7K]3 years ago
4 0

Answer : It is called as standard heat of formation.

Explanation :

Enthalpy of formation : The enthalpy of change when one mole of a pure compound is formed from its elements is called the enthalpy of formation. It is denoted as, \Delta H_f.

Standard heat of formation : When the reacting elements and the product formed are all in their standard state at 25^oC, the enthalpy change accompanying the chemical reaction is called the standard enthalpy of formation or standard heat of formation. It is denoted as, \Delta H_f^o.

Hence, it is called as standard heat of formation.

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What is buffers and mention its importance?
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Answer:

Buffer is the chemical substance that addition of acids and bases, maintaining constant environment,its called Buffer.

Explanation:

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5 0
3 years ago
W7L5 Stoichiometry Practice 2
Rzqust [24]

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

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6 0
2 years ago
How many grams of NaF form when .5 mol of HF reacts with excess Na2SiO3?
IgorLugansk [536]

Answer:

5.25g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is shown below:

Na2SiO3 + 8HF → H2SiF6 + 2NaF + 3H2O

From the balanced equation above,

8 moles of HF reacted to produce 2 moles of NaF.

Therefore, 0.5 moles of HF will react to produce = (0.5 x 2)/8 = 0.125 mole of NaF.

Next, we shall convert 0.125 mole of NaF to grams.

This is illustrated below:

Mole of NaF = 0.125 mole

Molar mass of NaF = 23 + 19 = 42g/mol

Mass of NaF =..?

Mass = mole x molar mass

Mass of NaF = 0.125 x 42

Mass of NaF = 5.25g

Therefore, 5.25g of NaF is produced from the reaction.

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3 years ago
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