Answer:
11.6 L will be the number of liters of carbon dioxide measured at STP.
Explanation:
The balanced equation for this combustion reaction is:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
where 1 mol of propane reacts to 5 moles of oxygen in order to produce 3 moles of carbon dioxide and 4 moles of water.
We assume the oxygen in excess, so the limiting reagent is the propane. Now, we determine the moles: 7.65 g . 1 mol/ 44 g = 0.174 moles
Ratio is 1:3. 1 mol of propane can produce 3 moles of CO₂
Therefore, 0.174 moles will produce (0.174 . 3) / 1 = 0.521 moles of CO₂
As 1 mol of gas is contained in 22.4L at STP conditions, we propose
22.4L / 1 mol = V₂ / 0.521 mol
22.4 L / 1 mol . 0.521 mol = V₂ → 11.6 L
D) Oxygen-17
Oxygen-17 is an isotope with 8 protons, 8 electrons, and 9 neutrons.
First we will calculate the number of moles of Iron:

, where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.

moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So

where 32 is the Atomical Weight of Oxygen (16 x 2).
=>

g