Explanation:
Relation between total pressure and mole fraction is as follows.

where,
= partial pressure of gas 1
= mole fraction of gas 1
= total pressure of the gases
Also, it is known that
= 1
or, 
It is given that total pressure of gas mixture is 0.51 atm and partial pressure of helium is 0.32 atm.
Hence, calculate the mole fraction of helium gas present in the given mixture as follows.

0.32 atm = 
= 0.63
As,
= 1
so, 
= 1 - 0.63
= 0.37
Hence, calculate the partial pressure of Ne as follows.


0.3084 atm = 

= 0.834 atm
Thus, we can conclude that the partial pressure of the Ne in the mixture is 0.834 atm.
Energy=mass x the speed of light squared.
Answer:
18 * 10^19 atoms
Explanation:
We must first convert 57.8 mg to grams.
If 1000 mg = 1g
57.8 mg = 57.8/1000 = 57.8 * 10^-3 g
Now;
If 1 gold atom has a mass of 3.27X10^-22 grams
x gold atoms have a mass of 57.8 * 10^-3 g
x = 57.8 * 10^-3 g/3.27X10^-22 g
x = 18 * 10^19 atoms
Answer:
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
Explanation:
Primary alcohols are stronger acids than secondary alcohols which are stronger than tertiary alcohols.
This trend is so because of the stability of the alkoxide ion formed(stabilising the base, increases the acidity). A more stabilised alkoxide ion is a weaker conjugate base (dissociation of an acid in water).
By electronic factors, When there are alkyl groups donating electrons, the density of electrons on th O- will increase a d thereby make it less stable.
By stearic factors, More alkyl group bonded to the -OH would mean the bulkier the alkoxide ion which would be harder to stabilise.
Down the group of the periodic table, basicity (metallic character) decreases as we go from F– to Cl– to Br– to I– because that negative charge is being spread out over a larger volume that is electronegativity decreases down the group.
Electronegative atoms give rise to inductive effect and a decrease in indutive effects leads to a decrease in acidity. Therefore an Increasing distance from the -OH group lsads to a decrease in acidity.
From above,
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol