Answer:
Na2CO3 <==> 2Na^+ + CO3^2-
Explanation:
Answer:
52 da
Step-by-step explanation:
Whenever a question asks you, "How long to reach a certain concentration?" or something similar, you must use the appropriate integrated rate law expression.
The i<em>ntegrated rate law for a first-order reaction </em>is
ln([A₀]/[A] ) = kt
Data:
[A]₀ = 750 mg
[A] = 68 mg
t_ ½ = 15 da
Step 1. Calculate the value of the rate constant.
t_½ = ln2/k Multiply each side by k
kt_½ = ln2 Divide each side by t_½
k = ln2/t_½
= ln2/15
= 0.0462 da⁻¹
Step 2. Calculate the time
ln(750/68) = 0.0462t
ln11.0 = 0.0462t
2.40 = 0.0462t Divide each side by 0.0462
t = 52 da
Answer:
![M_2=0.613M_1](https://tex.z-dn.net/?f=M_2%3D0.613M_1)
Explanation:
= Concentration of stock solution
= Concentration of solution
= Volume of stock solution = 19 mL
= Volume of solution = 0.31 L= 310 mL
We have the relation
![M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{M_119}{310}\\\Rightarrow M_2=M_1\times\dfrac{19}{310}\\\Rightarrow M_2=0.613M_1](https://tex.z-dn.net/?f=M_1V_1%3DM_2V_2%5C%5C%5CRightarrow%20M_2%3D%5Cdfrac%7BM_1V_1%7D%7BV_2%7D%5C%5C%5CRightarrow%20M_2%3D%5Cdfrac%7BM_119%7D%7B310%7D%5C%5C%5CRightarrow%20M_2%3DM_1%5Ctimes%5Cdfrac%7B19%7D%7B310%7D%5C%5C%5CRightarrow%20M_2%3D0.613M_1)
![\boldsymbol{\therefore M_2=0.613M_1}](https://tex.z-dn.net/?f=%5Cboldsymbol%7B%5Ctherefore%20M_2%3D0.613M_1%7D)
The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.
Answer:
CH3CH2CH2Cl
CH3CH2CH2CH2CH2SH
Br2
Explanation:
Dispersion forces increases with increase in relative molecular mass. The specie having the greater relative molecular mass definitely has greater dispersion forces. A rough estimation of the relative molecular masses of the species stated in the answer will reveal this fact.