Answer:
1. 6.37 KJ
2. 3.185 KJ
Explanation:
Gravitational potential energy is a form of potential energy with respect to the force of gravity.
Gravitational potential energy = mass x acceleration due to gravity x height
i.e PE = m x g x h
1. At the top of the platform; mass = 65 kg, acceleration due to gravity = 10 m/
, and height = 10 m.
Gravitational potential energy = 65 x 9.8 x 10
= 6370 Joules
The gravitational potential of the diver at the top of the platform is 6.37 KJ.
2. Halfway down; mass = 65 kg, acceleration due to gravity = 10 m/, and height = 5 m.
Gravitational potential energy = 65 x 9.8 x 5
= 3185 Joules
The gravitational potential energy of the diver halfway down is 3.185 KJ.
There are zero lone pairs of electrons on the central carbon atom in a Lewis Structure of CHI3. The correct option is b.
Explanation:
Lone pair electrons are those valence electrons of an atom which do not take part in bonding or left after the bonds are formed.
CH
carbon is the central atom in the compound having 4 valence electrons.
Each iodine molecule has 7 valence electrons.
H has 1 valence electron.
from the Lewis structure of CH, it is seen that all four valence electrons of the carbon is involved in bonding with 3 atoms of iodine and 1 atom of hydrogen.
Thus when all valence electrons are involved in bonding no lone pair of electron is found in CH that means zero lone pairs of electrons.
The octet of the iodine, carbon and hydrogen gets completed to form the compound.
I believe the answer is 15kg since after that there is 16kg and before there is 14kg
Answer:the energy required by an atom to lose or gain electron (e-) to be able to form ions.either cation or anion.
Explanation:
to lose or gain e- an atom has to donate or receive e- to to this it requires the more easily it can lose an electron the more electro positive it is and the more easily it gains electron the more electro negative it is.
Answer:
Percentage yield = 30%
Explanation:
Given data:
Number of moles of NO = 7.0 mol
Number of moles of O₂ = 5 mol
Number of moles of NO₂ = 3 mol
Percentage yield = ?
Solution:
Chemical equation:
2NO + O₂ → 2NO₂
Now we will compare the moles of NO₂ with NO and O₂ .
NO : NO₂
2 : 2
7.0 : 7.0
O₂ : NO₂
1 : 2
5.0 : 2 ×5.0 = 10 mol
The number of moles of NO₂ produced by NO are less it will be limiting reactant.
Mass of NO₂ = moles × molar mass
Mass of NO₂ = 10 mol × 46g/mol
Mass of NO₂ = 460 g
Actual yield of NO₂:
Mass of NO₂ = moles × molar mass
Mass of NO₂ = 3 mol × 46g/mol
Mass of NO₂ = 138 g
Percentage yield:
Percentage yield = Actual yield/theoretical yield × 100
Percentage yield = 138 g/ 460 g × 100
Percentage yield = 30%
