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sammy [17]
3 years ago
10

What is the source of the radioactivity in the sun

Physics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

Fusion of Hydrogen to form Helium

Explanation:

The sun is a big ball of gas and it provides solar energy that drives external processes on the earth surface.

The pressure and temperature within the sun provides energy to fuse abundant hydrogen atoms together to form helium atoms. This nuclear fusion process releases a huge amount of energy.

The fusion of hydrogen atoms to form helium is the source of radioactivity in the sun.

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At atmospheric pressure, what is the characteristic boiling point of water, in degrees Celsius?
xxMikexx [17]
Water boils at 100 degrees Celsius at atmospheric pressure.
4 0
4 years ago
What should a sailboat operator do when approaching a PWC head-on
nekit [7.7K]

<u><em>In accordance with the International Regulation for the prevention of collisions at sea</em></u><u>: </u>

<u>1.- A sailing boat has a passing preference over a motorized boat, </u><u>except when the motor boat is limited by its draft</u><u>. </u>

<u>2.- The sailboat must maintain its course and speed. </u>

<u>3.- </u><em><u>If it is evident that the PWC does not respond</u></em><u>, the sailboat must sound the warning signal, and change its course to starboard. </u>

<u>4.- </u><u><em>All actions must be taken as soon as possible</em></u><u>. </u>

<u>5.- If a sailboat is using its engine, the situation changes, and in that case, both ships must alter to starboard.</u>

8 0
3 years ago
ustapha Jones is speeding on the interstate in his Ferrari at 231km/hr when he passes a police car at rest . If the cop accelera
Lena [83]

Answer:

461 km/h

Explanation:

In order to solve this problem we must first sketch a drawing of what the situation looks like so we can better visualize it. (See attached picture).

We have two situations there, the first one is Mustapha's car that is traveling at a constant speed of 231km/hr.

The second situation is the police that is accelerating from rest until he reaches Mustapha. (We are going to suppose the acceleration is constant and that he will not stop accelerating until he reaches Mustapha). He has an acceleration of 15m/s^{2}.

We want to find what the final velocity of the police is at the time he reaches Mustapha. From this we can imply that the displacement x will be the same for both particles.

So let's model the first situation.

The displacement of Mustapha can be found by using the following equation:

V_{M}=\frac{x}{t}

when solving the equation for the displacement x we get that it will be:

x=V_{M}t

Now let's model the displacement of the cop. Since the cop has a constant acceleration, we can model his displacement with the following formula.

x=V_{0}t+\frac{1}{2}at^{2}

Since the initial velocity of the cop is zero, we can get rid of that part of the equation leaving us with:

x=\frac{1}{2}at^{2}

We can now set both equations equal to each other so we get:

\frac{1}{2}at^{2}=V_{M}t

When solving this for t, we get that:

t=\frac{2V_{M}}{a}  (let's call this equation 1)

Now, we know the cop has constant acceleration, so we can model it with the following formula too:

a=\frac{V_{f}-V_{0}}{t}

since the initial velocity of the cop is zero, we can get rid of that here too, so we get the following formula:

a=\frac{V_{f}}{t}

when solving for the final velocity, we get that:

V_{f}=at  (let's call this equation 2)

when substituting equation 1 into equation 2 we get:

V_{f}=a(\frac{2V_{M}}{a})

we can now cancel a leaving us with:

V_{f}=2V_{M}

This tells us that the final velocity of the cop will not depend on his acceleration. (This is only if the acceleration is constant all the time) So we get that the final velocity of the cop is:

V_{f}=2(231km/hr)

so

V_{f}=461km/hr

which is our answer.

8 0
3 years ago
The kinetic energy of a particle of mass 500g is 4.8j. Determine the velocity of the particle
musickatia [10]

Answer:

4.38 m/s

Explanation:

7 0
3 years ago
Read 2 more answers
Consider a 10 gram sample of a liquid with specific heat 2 J/gK. By the addition of 400 J, the liquid increases its temperature
stich3 [128]

40 J/g is the heat of vaporization of the liquid.

Answer: Option D

<u>Explanation:</u>

Given that mass of liquid sample: m = 10 g

And, Specific heat of the liquid: S = 2 J/g K

Also, the increase in the temperature of the liquid,  \Delta T = T_{2}-T_{1} = 10 K

Therefore, the total amount of heat energy required is given by:

              q_{1} = m \times S \times\left(T_{2}-T_{1}\right) = 10 \times 2 \times 10 = 200 J

According to the given data in the question,

Total heat energy supplied, q = 400 J

Rest of heat would be q_{2}=q-q_{1}=400-200=200 \mathrm{J}

Now, 200 J vaporizes the mass, half of the liquid from full portion boiled away. So,

                 m^{\prime} = \frac{10}{2} = 5 \mathrm{g}

Latent heat of vaporization of the liquid is L_{v}. It can be calculated as below,

                       q_{2} = m^{\prime} L_{v}

                       L_{v} = \frac{q_{2}}{m^{\prime}} = \frac{200}{5} = 40 \mathrm{J} / \mathrm{g}

5 0
3 years ago
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