The Hydronium ion concentration increases to 100 times the original concentration (10^2)
Answer: 38.2 μC
Explanation: In order to solve this problem we have to use the relationship for a two plate capacitor with a dielectric so:
C= Q/V= we also know that for two paralel plates C=εo*k*A/d and V=E/d
where k is the dielectric constant, A plate area, V is potential difference; E electric field and d the separation between the plates.
reorganizing we have:
Q/A=σ= E*k/εo= 1.2 * 10^6*3.6/8.85 * 10^-12=38.2μC
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Divide the flow rate (0.750 m³/s) by the cross-sectional area of each pipe:
diameter = 40 mm ==> area = <em>π</em> (0.04 m)² ≈ 0.00503 m²
diameter = 120 mm ==> area = <em>π</em> (0.12 m)² ≈ 0.0452 m²
Then the speed at the end of the 40 mm pipe is
(0.750 m³/s) / (0.00503 m²) ≈ 149.208 m/s ≈ 149 m/s
(0.750 m³/s) / (0.0452 m²) ≈ 16.579 m/s ≈ 16.6 m/s
