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igomit [66]
3 years ago
6

Ian walks 2 km to his best friend’s house, then walks 0.5 km to the library. He then makes a 2.5 km walk home. The entire walk t

ook him 3 hours. What is his average speed in km/h?
SHOW YOUR WORK!
Physics
1 answer:
Sonbull [250]3 years ago
4 0

Average speed = (total distance covered) / (time to cover the distance)

Ian's total distance = (2km + 0.5km + 2.5km) = 5 km

Ian's total time = 3 hours

Average speed = (5km) / (3 hours)

Average speed = 1.66 km/hr

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Serggg [28]

In a generator, mechanical energy is converted electrical energy. The answer is letter D. the mechanical energy in the generator produces energy by making the machines work and then transmitting this into the power lines of commercial industries, communities and others.

8 0
4 years ago
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FORMULA PLEASE AND explINATION
Alex_Xolod [135]

2 Newtons to the right.

3 newtons are needed to over come the friction. There are 2 left over.

So the answer is 2 newtons to the right.

5 - 3 = 2

7 0
3 years ago
(a) Calculate the number of free electrons per cubic meter for gold assuming that there are 1.5 free electrons per gold atom. Th
KonstantinChe [14]

Answer:

Part A:

n=8.85*10^{28}m^{-3}

Part B:

Electron Mobility=3.03*10^{-3} m^2/V

Explanation:

Part A:

To calculate the number of free electrons n we use the following formula::

n=1.5N-Au

Where N-Au is number of gold atoms per cubic meter

N-Au=\frac{Density*Avogadro Number}{atomic weight}

Density = 19.32g/cm^3

Avogadro Number=6.02*10^{23} atoms/mol

Atomic weight=196.97g/mol

So:

n=1.5*\frac{Density*Avogadro Number}{atomic weight}

n=1.5*\frac{19.32*6.02*10^{23}}{196.97}

n=8.85*10^{28}m^{-3}

Part B:

Electron Mobility=\frac{Elec-conductivity}{n * charge on electron}

n is calculated above which is 8.85*10^{28}m^{-3}

Charge on electron=1.602*10^{-19}

Elec- Conductivity= 4.3*10^{7}

Electron Mobility=\frac{4.3*10^{7}}{ 8.85*10^{28} * 1.602*10^{-19}}

Electron Mobility=3.03*10^{-3} m^2/V

4 0
4 years ago
If the Sun were to collapse into a black hole, the point of no return for an investigator would be approximately 3 km from the c
Marysya12 [62]

Answer:

1.97*10⁴N .He cannot survive.

Explanation:

The<em> </em><em>Tidal force</em> can be defined as the difference in force between center of  two bodies like center of earth and other bodies.This force stretches  the body too and fro from the center of mass of another body due to the difference in the gravitational force.

The tidal force is responsible for various phenomena like ocean tides,celestial body tearing up.

The tidal force is the effect of massive body gravitationally affecting another body.

The tidal force is the difference between the gravitational force of two bodies and directly proportional to the mass of body affecting another body and inversely proportional to the square of radius of the distance between center and the object.

Here let us consider height of person as 2m and d=1m

  ΔF=\frac{GMm}{(R-d)^{2} } -\frac{GMm}{(R+d)^{2} }

       =GMm[\frac{1}{(R-d)^{2} }-\frac{1}{(R+d)^{2} }]

         =(6.67*10⁻¹¹)(1.99*10³⁰)(1.0)[\frac{1}{(300*10^3-1)^{2} }-\frac{1}{(300*10^3+1)^{2} }}

   ΔF=1.97*10⁴N.

Thus he cannot survive

           

4 0
3 years ago
Part A What is the resistance of a 4.4 m length of copper wire 1.3 mm n diameter? The resistivity of copper is 1.68x 10-8 Ω-m Ex
Natalija [7]

Explanation:

It is given that,

Length of the copper wire, l = 4.4 m

Diameter of copper wire, d = 1.3 mm = 0.0013 m

Radius of copper wire, r = 0.00065 m

The resistivity of the copper wire, \rho=1.68\times 10^{-8}\ \Omega-m

We need to find the resistance of the copper wire. It is given by :

R=\rho\dfrac{l}{A}

R=1.68\times 10^{-8}\ \times \dfrac{4.4\ m}{\pi (0.00065)^2}

R =0.055 ohms

So, the resistance of the copper wire is 0.055 ohms. Hence, this is the required solution.

7 0
3 years ago
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