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Troyanec [42]
3 years ago
10

Which one of the following factors would not speed up a chemical reaction?

Chemistry
1 answer:
gladu [14]3 years ago
5 0
D. Making the reactant particles larger
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Thinner in the center that at the edges; virtual image smaller.
ipn [44]
<h3><u>Answer</u>;</h3>

Concave Lenses

<h3><u>Explanation</u>;</h3>
  • A concave lens is thin in the middle and thick at the edges, such that it seems to cave inwards. It spreads light rays apart producing an image smaller than the actual object.
  • <em><u>Images formed by a concave lens are virtual, upright, reduced in size and located on the same side of the lens as the object. Diverging lenses or concave lens always produce images that share these characteristics. The location of the object does not affect the characteristics of the image. </u></em>
3 0
3 years ago
Read 2 more answers
If the rate of a reaction increases by a factor of 64 when the concentration of reactant increases by a factor of 4, what is the
igomit [66]

The reaction is of order three with respect to the reactant.

<h3>Explanation</h3>

The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if  concentrations of any other reactants stay constant in the whole process.

In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)

In this question,

[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.

In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.

It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:

\ln{4^n} = \ln{64}\\n\; \ln{4} = \ln{64}\\n = \frac{\ln{64}}{\ln{4}} = 3.

Evaluating \ln(64) / \ln(4) on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.

n = 3. Therefore, the reaction is of order three with respect to this reactant.

3 0
3 years ago
Consider the chemical equations shown here.
Alona [7]

Answer:

-304.1

Explanation:

Just took it on Edge 2020

5 0
2 years ago
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Please Be Honest<br><br> Rate 1-10
san4es73 [151]
Also give you a 10, the last one looks really nice
5 0
2 years ago
4. Which elements would have similar properties to potassium?
iren [92.7K]

Answer:

The answer is A. Lithium and Sodium

5 0
2 years ago
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