4NH3+5O2 <=>4NO + 6H2O
Using the definition of Kp, we have
Kp=(Pno^4*Ph2o^6)/(Pnh3^4*Po2^5)
where Pno=partial pressure of NO, etc.
The numerical value for a given temperature can be evaluated when the actual partial pressures are known.
Volume of Argon V1 = 5.0 L
Pressure of Argon P1 = 2 atm
Final temperature T2 = 30 C = 30 + 273 = 303 K
Volume at final temperature V2= 6 L
Pressure at final temperature P2 = 8 atm
We know that (P1 x V1) / T1 = (P2 x V2) / T2
(2 x 5)/ T1 = (8 x 6)/ 303 => T1 = (10 x 303) / 48
Initial Temperature T1 = 3030 / 48 = 63.12
Initial Temperature = -209. 8 C
Answer:
the types of chemical reaction are combination, decomposition, single replacement, double replacement, combustion
<u>We are given:</u>
The force applied on the poor hamster (F) = 12 N
Acceleration of the poor Hamster (a) = 8 m/s²
<u>Solving for the mass of the Poor Hamster:</u>
From newton's second equation of motion, we know that:
F = ma
<em>replacing the given values</em>
12 = 8 * m
m = 12/8 kg
m = 3/2 kg
The poor Hamster weighs 3/2 kg
