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kkurt [141]
4 years ago
11

1. What happens in the process of radioactive decay? What is the half-life of a radioactive substance, and how is it used to dat

e an object?
Physics
1 answer:
Ierofanga [76]4 years ago
6 0
<span> In radioactive decay, an unstable atomic nucleus emits particles or radiation and converts to a different atomic nucleus. If the new nucleus is unstable, it will decay again, until eventually, a stable nucleus is formed. Such a sequence of nuclear decays forms a decay series.

The half-life of a radioactive substance is the time required for half of the atoms of a radioactive isotope to decay. If you have, say, 1 million atoms of a specific isotope in a sample, the time required for 500,000 of those atoms to decay is the half-life of that specific isotope. If you have 50 atoms of that isotope, 25 atoms will decay in the same amount of time.

Because the half-life is fixed for a specific isotope, it can be used to date objects. You compare the decay rate of an old object with the decay rate of a fresh sample. Nuclear decay is a first-order process and can be described by a specific mathematical equation, which depends on the decay rate and the half-life. Knowing those values, you can work back and determine the age of an object, as compared with a standard sample. Old objects will not have as much of a radioactive isotope in them as new objects, since the isotopes will have decayed over time in the old object.</span>
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Which of the following is not a component of a normal experiment?
MaRussiya [10]

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

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Explanation:

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How can you increase the torque you are putting on a lever, without exerting any more force?
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See below

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3 years ago
During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t^2 to s
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Answer:

70560 m

Explanation:

The formula to calculate the distance travelled during a free fall motion is

d=-\frac{1}{2}gt^2

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In this situation,

t = 120 s

Therefore the distance travelled after 120 s is

d=-\frac{1}{2}(-9.8)(120)^2=70560 m

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4 years ago
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