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mrs_skeptik [129]
3 years ago
8

Ouabain is a poison that binds to the Na+/K+ pump in the cell membrane and inhibits its action. The expected result of this pois

on on secondary active transport is ______________________________.
Chemistry
1 answer:
IRISSAK [1]3 years ago
5 0

Answer: A loss of the ion concentration gradient that drives this process.

Explanation:Ouabain known as g-strophanthin, is a cardiac glycoside that can be medically used to treat hypotension.It acts by nhibiting the sodium - potassium (Na/K-ATPase) by causing a loss of the ion concentration gradient that drives it's process. Originally, it was a toxic plant that was used as an arrow poison in eastern Africa for hunting and warfare. Recently, Ouabain is synthesized by animals and secreted from the adrenal cortex to regulate body osmosis.

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The superheated water vapor is at 15 MPa and 350°C. The gas constant, the critical pressure, and the critical temperature of wat
Vesnalui [34]

Answer:

0.01917 m^3/kg.

Explanation:

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P = 15 MPa

= 1.5 × 10^4 kPa

T = 350 °C

= 350 + 273

= 623 K

Molar mass of water, m = (2 × 1) + 16

= 18 g/mol

= 0.018 kg/mol

R = 0.4615 kPa·m3/kg·K

Using ideal gas equation,

P × V = n × R × T

But n = mass/molar mass

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4 0
3 years ago
A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL
d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

pH = 0.70

Putting values in above equation, we get:

0.70=-\log[H^+]

[H^+]=10^{-0.70}=0.199M

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated nitric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted nitric acid solution

We are given:

M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL

Putting values in above equation, we get:

7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL

Hence, the volume of concentrated solution required is 9.95 mL

6 0
3 years ago
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