How many liters of carbon dioxide at STP can be produced when 144 g of pentane (C5H12) reacts with excessive oxygen?

Chemistry

1 answer:

EleoNora [17]2 years ago

8 0

Answer:

Explanation:

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TEA [102]

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$K=\frac{[CaO][CH_{4}][H_{2}O ]^{2} }{[CaCO_{2}][H_{2}]^4 }$

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The equilibrium expression is the K value equal to the product of the concentrations of the products over the product of the concentrations of the reactants. If there is a coefficient in front of the compound, raise the molecule to that power.

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