Question

If a cannonball were launched with a speed of 37m/s at a 60° angle from the height of Om, what would be the cannonball's range?

Answer 1

Answer:

Range = 120.98 m, (or rounded to the nearest whole number =121 meters)

Explanation:

We can use the formula for range in projectile motion at ground level:

$Range = \frac{v^2\,\,sin(2\theta)}{g} \\Range= \frac{37^2\,\,sin(120)}{9.8} \\Range\approx 120.98\,\,m$

Then the cannon's range would be approximately 120.98 m, which may be rounded to the nearest whole number as 121 meters