All categories

3 years ago

If a cannonball were launched with a speed of 37m/s at a 60° angle from the height of Om, what would be the cannonball's range?

Physics

1 answer:

JulijaS [17]3 years ago

8 0

Answer:

Range = 120.98 m, (or rounded to the nearest whole number =121 meters)

Explanation:

We can use the formula for range in projectile motion at ground level:

$Range = \frac{v^2\,\,sin(2\theta)}{g} \\Range= \frac{37^2\,\,sin(120)}{9.8} \\Range\approx 120.98\,\,m$

Then the cannon's range would be approximately 120.98 m, which may be rounded to the nearest whole number as 121 meters

You might be interested in

A tennis ball and a solid steel ball of the same diameter are dropped at the same time. Ignoring the air resistance effects, whi

Paha777 [63]

Yes I have the answer

6 0

3 years ago

If two runners take the same amount of time to run a mile, they have the same __________.

Svet_ta [14]

I am going to say velocity because you have the same amount of acceleration going in a certain direction.

8 0

3 years ago

Read 2 more answers

15. Sandra decided to talk a walk at her neighborhood park. She walks 20 meters

FinnZ [79.3K]

Answer:

Long question good luck:)..............

Explanation:

8 0

3 years ago

A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.

MrRissso [65]

Answer:

(a). The distance is 49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

$d=u\cos\theta\times t$

Put the value into the formula

$d=20\cos40\times3.25$

$d=49.79\ m$

(b). We need to calculate the horizontal velocity

Using formula of velocity

$v_{x}=u\cos\theta$

Put the value into the formula

$v_{x}=20\times\cos40$

$v_{x}=15.3\ m/s$

We need to calculate the vertical velocity

Using equation of motion

$v_{y}=u\sin\theta-gt$

Put the value into the formula

$v_{y}=20\sin40-9.8\times3.25$

$v_{y}=-19\ m/s$

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

$v=\sqrt{v_{x}^2+v_{y}^2}$

$v=\sqrt{(15.3)^2+(19)^2}$

$v=24.39\ m/s$

Hence, (a). The distance is 49.79 m.

(b). The speed of the ball is 24.39 m/s.

4 0

3 years ago

Approximately what core temperature is required before hydrogen fusion can begin in a star?

valkas [14]

Answer:

The temperature required is near about 3 million kelvin

Explanation:

The brilliance of the star results from the nuclear reaction that take place in the core of the star and radiate a huge amount of thermal energy resulting from the fusion of hydrogen into helium.

For this reaction to take place, the temperature of the star's core must be near about 3 million kelvin.

The hydrogen atoms collide and starts and the energy from the collision results in the heating of the gas cloud. As the temperature comes to near about $1.5\times 10^{7 {\circ}C$ , the nuclear fusion reaction takes place in the core of the gas cloud.

The huge amount of thermal energy from the nuclear reaction gives the gas cloud a brilliance resulting in a protostar.

8 0

3 years ago