Two small identical conducting spheres are suspended near each other on thin insulating threads of equal length. They are both c
1 answer:
Answer:
Explanation:
It is given that initially sphere has different charges and momentarily brought in contact with each other.
When the spheres are touched then charge is equally redistributed among spheres such that now they possess the equal amount of charges.
When they are suspended from the thread their separation increases compared to previous situation because now the value of force increases because of the change in the product of charges.
For example, Suppose initially they possess 15 C and 17 C charge and after redistribution they both possess 16 C of charge.
Product of charges
Final Product of charges
As force depends upon the Product of the charges so there will be more repulsive force.
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Answer:
Explanation:
Given
ambient Pressure =98.10 kPa
(a)gauge pressure 152 kPa
we know
Absolute pressure=gauge pressure+Vacuum Pressure
=152+98.10=250.1 kPa or 36.27 psi
(b)=67.5 Torr or 8.99 kpa
as 1 Torr is 0.133 kPa
=8.99+98.10=107.09 kPa or 15.53 psi
(c)=0.1 bar or 10 kPa
Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi
as 1 kPa is equal to 0.145 psi
(d)=0.84 atm or 85.113 kPa
as 1 atm is equal to 101.325 kPa
=98.10-85.11=12.99 kPa or 1.88 psi
Recall that
where is the luger's initial velocity,
his final velocity,
his acceleration, and
the distance he traverses. Then
so the closest answer is C.