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3 years ago

7

you paddle a canoe with the force of 200N. you and the canoe have a combined mass of 97KG . what is the acceleration of the cano

e?

1 answer:

erastovalidia [21]3 years ago

6 0

Use Newton's (second) Law:
$F=ma$
with your data:
$200=97a$
$a=2m/s^{2}$

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What four elements composed everything in nature according to the beliefs of the ancient greeks? air, earth, fire, and water air

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The ancient Greeks, in a theory that was suggested around 450 BC, believed that everything was from from four elements. These elements included earth, water, air and fire. Later, Aristotle supported this theory.

Therefore, the first option is correct.

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A rotating flywheel has moment of inertia 18.0 kg⋅m^2 for an axis along the axle about which the wheel is rotating. Initially th

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The rotational kinetic energy takes 0.430 seconds to become half its initial value.

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Where:

$\Delta E$ - Energy losses, measured in joules.

$K_{1}$ , $K_{2}$ - Initial and final rotational kinetic energies, measured in joules.

By definition of rotational kinetic energy, we expand the equation above:

$\Delta E = \frac{1}{2}\cdot I\cdot (\omega_{1}^{2}-\omega_{2}^{2})$ (2)

Where:

$I$ - Moment of inertia of the flywheel, measured in kilograms per square meter.

$\omega_{1}$ , $\omega_{2}$ - Initial and final angular speed, measured in radians per second.

If we know that $K_{1} = 30\,J$ , $K_{2} = 15\,J$ and $I = 18\,kg\cdot m^{2}$ , then the initial angular speed is:

$K_{1} = \frac{1}{2}\cdot I \cdot \omega_{1}^{2}$ (3)

$\omega_{1}=\sqrt{\frac{2\cdot K_{1}}{I} }$

$\omega_{1} = \sqrt{\frac{2\cdot (30\,J)}{18\,kg\cdot m^{2}} }$

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$\omega_{2}=\sqrt{\frac{2\cdot K_{2}}{I} }$

$\omega_{2} = \sqrt{\frac{2\cdot (15\,J)}{18\,kg\cdot m^{2}} }$

$\omega_{2} \approx 1.291\,\frac{rad}{s}$

$\omega_{2} \approx 0.205\,\frac{rev}{s}$

Under the assumption that flywheel is decelerating uniformly, we get that the time taken for the flywheel to slowdown is:

$t = \frac{\omega_{2}-\omega_{1}}{\alpha}$ (5)

If we know that $\omega_{1}\approx 0.291\,\frac{rev}{s}$ , $\omega_{2} \approx 0.205\,\frac{rev}{s}$ and $\alpha = -0.200\,\frac{rev}{s^{2}}$ , then the time needed is:

$t = \frac{0.205\,\frac{rev}{s}-0.291\,\frac{rev}{s}}{-0.200\,\frac{rev}{s^{2}} }$

$t = 0.43\,s$

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3 years ago

In a church choir loft, two parallel walls are 5.30 m apart. The singers stand against the north wall. The organist faces the so

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The virtual image is as far behind the mirror as the choir is in front of the mirror. Thus, the image is 5.30 m behind the mirror. The image of the choir is 0.800 m+ 5.30 m= 6.10 m from the organist.

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<h3><u>The concept of Ray Optics and Optical Instrument</u></h3>

A subject of physics called Ray Optics and Optical Instruments investigates the characteristics and behavior of light. When light moves in a straight line, as in ray optics, also known as geometrical optics, it is said that every object has an image. The optical tools that are now in use make use of the reflecting and refracting qualities of mirrors, lenses, and prisms.

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The theory of ray optics, often known as geometrical optics, describes how light travels in terms of rays. It discusses how light behaves. Typically, light is thought of as a beam that follows a straight path.

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1 year ago

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Where;

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Thus, the final velocity of the 15 kg mass after the collision is 18.33 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

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2 years ago