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Alexeev081 [22]
3 years ago
11

A fast moving super hero in a comic book runs around

Physics
2 answers:
____ [38]3 years ago
7 0
That would be The Flash. 
Korolek [52]3 years ago
4 0
Superman, superwoman
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What is the momentum of a 5 kg object that has a velocity of 1.2 m/s?
guajiro [1.7K]
In the given question all the required details are given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.
We know the equation of finding momentum as
Momentum = mass * velocity
                   = 5 * 1.2
                   = 6
So the momentum of the object is 6 Newton.
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3 years ago
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State the Newton's first law of motion in words and in mathematical form.
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<em>Newton's First Law</em>

<em>*</em><em> </em><em>Newton's First Law of Motion states that a body will remain at rest or will continue to move at a constant velocity, unless an external force is applied.</em>

<em>*</em><em> </em><em>This means that in order for the acceleration of a body to change, there must be a net force applied to the body. Put another way, if the forces on an object balance, there will be no acceleration (the object will continue at the same speed).So, if we are told that a body is not accelerating (i.e. if it is moving at a constant velocity), we know that the resultant (overall) force in any one direction will be zero.</em>

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<em> </em><em>8</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>f</em><em>t</em><em>,</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>o</em><em>w</em><em>a</em><em>r</em><em>d</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>i</em><em>g</em><em>h</em><em>t</em><em>.</em>

<em>F</em><em> </em><em>=</em><em> </em><em>F</em><em>2</em><em> </em><em>-</em><em> </em><em>F</em><em>1</em>

<em>=</em><em> </em><em>2</em><em>0</em><em>N</em><em> </em><em>-</em><em> </em><em>8</em><em>N</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>N</em>

<em>F</em><em> </em><em>=</em><em> </em><em>m</em><em>a</em>

<em>a</em><em> </em><em>=</em><em> </em><em>F</em><em>/</em><em>m</em>

<em>a</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>N</em><em>/</em><em>5</em><em>k</em><em>g</em>

<em>a</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em> </em><em>m</em><em>/</em><em>s</em><em>^</em><em>2</em>

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Mr. Llama walked from his house to the bus stop. The bus stop is 2 miles from his house. He returned back to his house from the
Hoochie [10]

Answer:

Displacement of Mr. Llama: Option D. 0 miles.

Explanation:

The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.

For Mr. Llama:

  • Final position: Mr. Llama's house;
  • Initial position: Mr. Llama's house.

The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.

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