The projectile has a height <em>h</em> at time <em>t</em> given by
<em>h</em> = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for <em>t</em> when <em>h</em> = 0 :
0 = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²
0 = 1/2 <em>t</em> (28.0 m/s - <em>g t</em> )
1/2 <em>t</em> = 0 <u>or</u> 28.0 m/s - <em>g</em> <em>t</em> = 0
The first equation says <em>t</em> = 0, which refers to the moment the gun is first fired, so we ignore that solution. We're left with
28.0 m/s - <em>g t</em> = 0
<em>t</em> = (28.0 m/s) / <em>g</em>
<em>t</em> = (28.0 m/s) / (9.80 m/s²)
<em>t</em> ≈ 2.86 s
yes because your mass doesn't change but your weight can
ex- if you travel to Saturn your weight would change but your mass would stay the same
<span>If a plane has a velocity of 300 km/h and a tailwind of 20 km/h, then the vectors of both forces would add (assuming that the tailwind is blowing exactly at the airplanes back) to a total of 320 km/h. Hope it helps
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Answer:
The displacement is 386.16m
Explanation:
A seal dives to a depth of 248m. To find displacement, we must calculate the resultant vectors which will give us the displacement
R= sqrt(vector1+vector2)
Since this is a right angle triangle
R= sqrt(248^2 + 296^2)
R= sqrt(149120)
R= 386.16m
Displacement = 386.16m
Distance covered is given as follows
1). 7 km North
2). 5 km North
3). 1 km East
Now total distance covered will be given as
Now in order to find the displacement we will show all with their directions
towards North
towards East
So total displacement is
so net displacement will be
so displacement is 12.04 km
