Answer:
Explanation:
Given
Diameter(D)=21.5 cm
distance between plate=1.75 mm
and we know capacitance is
and we know charge is
Q=CV
and charge density (![\sigma [tex])[tex]=\frac{Q}{A}=\frac{\epsilon _0AV}{Ad}=\frac{\epsilon V}{d}](https://tex.z-dn.net/?f=%5Csigma%20%5Btex%5D%29%5Btex%5D%3D%5Cfrac%7BQ%7D%7BA%7D%3D%5Cfrac%7B%5Cepsilon%20_0AV%7D%7BAd%7D%3D%5Cfrac%7B%5Cepsilon%20V%7D%7Bd%7D)
Electric field(E)
Energy density
Energy desity
Energy desity![=\frac{1}{8\pi \cdot 9\times 10^9}\times \left [ \frac{12\times 10^3}{1.75}\right ]^2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B8%5Cpi%20%5Ccdot%209%5Ctimes%2010%5E9%7D%5Ctimes%20%5Cleft%20%5B%20%5Cfrac%7B12%5Ctimes%2010%5E3%7D%7B1.75%7D%5Cright%20%5D%5E2)
Answer:
A spring is compressed and held at compression by a person before releasing it
Explanation:
All the other answers are showing things that are at rest and have no energy starting nor going through them. This answer show how the energy is starting and being released.
Answer:
160,000 N
Explanation:
Given:
m = 320,000 kg
v₀ = 0 m/s
a = constant
t = 57 s
Δx = 810 m
Find: Fnet
Apply Newton's second law:
∑F = ma
Fnet = ma
To find Fnet, we must first find the acceleration.
x = x₀ + v₀ t + ½ at²
810 m = 0 m + (0 m/s) (57 s) + ½ a (57 s)²
a = 0.50 m/s²
Fnet = (320,000 kg) (0.50 m/s²)
Fnet = 160,000 N
The answer to that is c hope it helps
True is the correct answer hope this helps
