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garik1379 [7]
4 years ago
15

HELP!! PICTURE ATTACHED!

Physics
2 answers:
tamaranim1 [39]4 years ago
8 0
Question 17:

At point A, the snowboarder is on the point of moving and the potential energy would be at its maximum (the particle has to work against the force of gravity). The kinetic energy is zero since the snowboarder is not yet moving (has no velocity). 

Question 18:

At point C, the kinetic energy will be zero and the potential energy will be minimum. As the snowboarder moves from point C to B, there will be a transfer between the kinetic energy to the potential energy. At point B, the potential energy will be back to maximum.
yulyashka [42]4 years ago
4 0

17. At point A, the snowboarder has potential energy

Explanation:

There are two types of energy involved here:

- Gravitational potential energy: this is the energy related to the height of the snowboarder, and it is given by U=mgh, where m is the mass of the snowboarder, g is the gravitational acceleration and h is the height of the snowboarder relative to the ground

- Kinetic energy: this is the energy related to the motion of the snowboarder, and it is given by K=\frac{1}{2}mv^2, where v is the speed of the snowboarder

We see that at point A the snowboarder is located at a higher point, so h is larger, therefore he has gravitational potential energy.


18. From point C to point B, kinetic energy is converted into potential energy

Explanation:

The law of conservation of energy states that the mechanical energy (sum of potential and kinetic energy: E=U+K) is constant. At point C, the snowboarder is located at height h=0, so he only has kinetic energy (in fact, its speed is maximum at point C). As he moves towards point B, he increases his height: therefore, its potential energy increases, while his kinetic energy decreases (this implies that his speed decreases as well). Therefore, kinetic energy is converted into potential energy.

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Answer:

The force of the ball on the bat is same as the force of the bat on the ball.  

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According to the Newton's third law, for every action there is an equal and opposite reaction.

The action and the reaction forces acts on the two different bodies but the magnitude of the force is same.  

As the ball is hitted by the bat, the bat exerts the force on the ball and the same force is exerted on the bat by the ball according to the Newton's third law.

So, the force of the ball on the bat is same as the force of the bat on the ball but the direction of force is opposite.  

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How wood helps in home insulation plz answer fast<br>plz answwweeeeeeerrrrrrr
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Wood is a poor conductor and therefore a good insulator keeping heat inside
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A car going 22 m/s increases its speed to pass a truck. Five seconds later the car is going 35 m/s. Calculate the acceleration o
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A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the d
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A proton moves with a velocity of v with arrow = (4î − 6ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î
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Answer:

F = [(6.4 × 10⁻¹⁹)î + (8.0 × 10⁻¹⁹)ĵ + (22.4 × 10⁻¹⁹)k] N

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Explanation:

The magnetic force, F, on a given charge, q, moving with velocity, v, in a magnetic field, B, is given as the vector product

F = qv × B

where v = (4î − 6ĵ + k) m/s

B = (î + 2ĵ − k) T

The particle is a proton, hence,

q = (1.602 × 10⁻¹⁹) C

F = qv × B = q (v × B)

(v × B) is given as (4î − 6ĵ + k) × (î + 2ĵ − k)

The cross product is evaluated as a determinant of

| î ĵ k |

|4 -6 1 |

|1 2 -1 |

î [(-6)(-1) - (2)(1)] - ĵ [(4)(-1) - (1)(1)] + k [(4)(2) - (-6)(1)]

î (6 - 2) - ĵ (-4 - 1) + k (8 + 6) = (4î + 5ĵ + 14k)

(v × B) = (4î + 5ĵ + 14k)

F = q (v × B) = (1.6 × 10⁻¹⁹) (4î + 5ĵ + 14k)

F = [(6.408 × 10⁻¹⁹)î + (8.01 × 10⁻¹⁹)ĵ + (22.428 × 10⁻¹⁹)k] N

Magnitude of F =

√[(6.408 × 10⁻¹⁹)² + (8.01 × 10⁻¹⁹)² + (22.428 × 10⁻¹⁹)²]

Magnitude of F = (2.466 × 10⁻¹⁸) N

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